Given:
p = 7.6% = 0.076, the percentage of people who stay overnight at the hospital.
E = 1.5% = 0.015, margin of error
95% confidence interval.
The standard error is
Es = \sqrt{ \frac{p(1-p)}{n} }
where
n = the sample size.
The margin of error is
E=z^{*}E_{s}
where
z* = 1.96 at the 95% confidence level.
Because the margin of error is given, there is no need to calculate it.
The 95% confidence interval is
p +/- E = 0.076 +/- 0.015 = (0.061, 0.091) = (6.1%, 9.1%)
Answer:
The 95% confidence interval is between 6.1% and 9.1%.
Answer: The average rate of change is 6.First, plug in each value of <em>t</em> into the function, v(t) to find there coordinate pairs.
v(2) = (2)^2 - (2) + 10
v(2) = 4 + 8
v(2) = 12
v(5) = (5)^2 - (5) + 10
v(5) = 25 + 5
v(5) = 30
You can write these values as coordinate pairs, like so: (2, 12) and (5, 30).
The formula for the average rate of change is

. When you plug in the values from this particular case, the average rate of change formula becomes

, or

.
Looking at the equation, you can solve for the average rate of change between t = 2 and t = 5, which equals
6.
Answer:
distributive property of multiplication
Step-by-step explanation:
To find this, multiply 9.2 by the decimal form of the percent (4.75). The answer is 43.7
Answer:
300.00
Step-by-step explanation: