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inna [77]
3 years ago
6

the ending retained earnings balance of boomer inc. decreased by $1.0 million from the beginning of the year. the company declar

ed a dividend of $5.4 million during the year. what was the net income for the year?
Mathematics
1 answer:
almond37 [142]3 years ago
8 0

Answer:

yes

Step-by-step explanation:

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Can more than one triangle be drawn if you are given the specifications of two side lengths and one angle? yes or no
Vladimir [108]

Answer:no

Step-by-step explanation:

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3 years ago
Randolph is trying to find the equation of a line parallel to y = '1 over 4 x − 6 in slope-intercept form that passes through th
Aleksandr [31]
So remember that paralell lines have the same slope
y=1/4x-6
1/4=slope
so we set up a new equation in slope intercept form
y=mx+b
m=slope
b=y-intercept

y=1/4x+b

one solution si (-1,5) where x=-1 and y=5
subsitute
5=1/4(-1)+b
5=-1/4+b
add 1/4 to both sides
5+1/4=21/4=b

the answer is y=1/4x+21/4


4 0
3 years ago
Read 2 more answers
Which expression is NOT EQUAL TO 30?
Debora [2.8K]
3rd one =104
((2×60)÷30)×(24+2)=104
8 0
3 years ago
Giving brainliest!!<br> pls answer correctly
Semmy [17]

Answer:

DISCLAIMER:I'M NOT REALLY GOOD AT MATH

Surface area=¶r squared.

¶=3.14

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=10/2

5

therefore,3.14×5×5

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7 0
3 years ago
(a) Show that the volume of a metal sphere of radius 15 cm is 14140 cm”, correct to 4 significant
Sladkaya [172]

Answer:

a) The volume of the sphere is approximately 14,137.16694 which is 14,140 cm³ correct to 4 significant figures

b) The volume of water required to fill the tank is approximately 103,670 cm³

Step-by-step explanation:

a) In the question, the radius of the sphere, r = 15 cm

The formula for the volume, 'V', of a sphere is given as follows;

V = \dfrac{4}{3} \times \pi \times r^3

Where;

r = The radius of the the sphere

V = The volume of the sphere

Plugging in the value for the radius, 'r', of the sphere, in the equation for, 'V', we get;

V = \dfrac{4}{3} \times \pi \times 15^3 \approx = 14,137.16694

Therefore;

The volume of the sphere to 4 significant figures is V ≈ 14,140 cm³

b) The parameters of the cylindrical tank are;

The height of the cylindrical tank, h = 60 cm

The radius of the cylindrical tank, r = 25 cm

The volume of a cylinder, V = π·r²·h

∴ The volume of the cylindrical tank without water, 'V_t', is given as follows;

V_t = π × (25 cm)² × 60 cm ≈ 117809.72451 cm³

The volume of water, V_{water}, required to fill the tank with the sphere of volume 'V' placed inside is given as follows

V_t = V + V_{water}

∴ V_{water} = V_t - V

From which we get;

V_{water} ≈ 117809.72451 cm³ - 14,140 cm³ = 103,669.72451 cm³ ≈ 103,670 cm³

The volume of water required to fill the tank, V_{water} ≈ 103,670 cm³.

8 0
3 years ago
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