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7nadin3 [17]
3 years ago
15

Randolph is trying to find the equation of a line parallel to y = '1 over 4 x − 6 in slope-intercept form that passes through th

e point (−1, 5). Which of the following equations will he use? (6 points)
Mathematics
2 answers:
Gnom [1K]3 years ago
7 0

Answer:

y - 5 = \frac{1}{4} (x - (-1))      The First Option

Step-by-step explanation:

if your on question 13 of (04.02 MC)

then that should be the answer.

Aleksandr [31]3 years ago
4 0
So remember that paralell lines have the same slope
y=1/4x-6
1/4=slope
so we set up a new equation in slope intercept form
y=mx+b
m=slope
b=y-intercept

y=1/4x+b

one solution si (-1,5) where x=-1 and y=5
subsitute
5=1/4(-1)+b
5=-1/4+b
add 1/4 to both sides
5+1/4=21/4=b

the answer is y=1/4x+21/4


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Solve for y. answer to the nearest tenth & solve for x. NEED HELP WITH BOTH THESE QUESTIONS !!
Inessa [10]

Answers:

5. x = 1

6. y = 11.5

Step-by-step explanation:

For question 5, you can use power of a point which describes the relationship of two secants intersecting inside a circle. You get the formula:

AC * CD = BC * CE

You can substitute the values you are given to get:

2 * 4 = x * 8

This gives you x = 1

For question 6, you can use another formula in power of a point that describes two secants intersecting in the exterior of a circle. You get the formula:

GH * GJ = GI * GK

Using segment addition postulate, you get:

GJ = GH + HJ = 5 + 16 = 21

GK = GI + IK  = 6 + y --> y + 6

Now, substitute into the equation from power of a point:

5 * 21 = 6 * (y + 6)

105 = 6 * (y + 6)

17.5 = y + 6

y = 11.5

4 0
3 years ago
Anyone needs help on circumference or area of a circle?
riadik2000 [5.3K]
No circumference of a circle is very easy to me
5 0
3 years ago
George finished 10 of 25 math problems.what percent of the problems did george finish
PIT_PIT [208]

Answer:

40%

Step-by-step explanation:

So 10/25=0.4

0.4=40%

8 0
3 years ago
Read 2 more answers
What does 100,000 • 1,470 • 300,890 • 69 =
Mazyrski [523]
If you multiply them all you get 3.0519273e+15 as your answer.
5 0
3 years ago
Three consecutive odd integers are such that the square of the third integer is 1515 greater than greater than the sum of the sq
Ksju [112]
Let
x-----------> first <span>odd integer
x+2--------> second consecutive odd integer
x+4-------> third consecutive odd integer

we know that
(x+4)</span>²=15+x²+(x+2)²-------> x²+8x+16=15+x²+x²+4x+4
x²+8x+16=19+2x²+4x-------> x²-4x+3
x²-4x+3=0

using a graph tool----------> to calculate the quadratic equation
see the attached figure
the solution is
x=1
x=3

the answer is
the first odd integer x is 1
the  second consecutive odd integer x+2 is 3
the third consecutive odd integer x+4 is 5

7 0
4 years ago
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