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scZoUnD [109]
3 years ago
8

Line segment XY was used to draw a copy of ABC.XY is 3.5 centimeters long. What is the length of

Mathematics
2 answers:
hoa [83]3 years ago
7 0

Answer:

The length of  AA' + BB'+CC' is 10.5 cm

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

A translation is a transformation that does not modify the shape or size of the figure. In a translation all the points of the figure will move the same distance and direction.

In this problem

AA'=BB'=CC'=XY

we have that

XY=3.5\ cm

so

AA'+BB'+CC'=3.5+3.5+3.5=10.5\ cm

therefore

The length of  AA' + BB'+CC' is 10.5 cm

Tresset [83]3 years ago
4 0

3.5(3)=10.5 this i the answer. I had this for hw.

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Simplify: ? (10x = 105 - (12x – 247)​
Greeley [361]

Answer:

x = 16

Step-by-step explanation:

10x = 105 - (12x - 247) //Distribute - sign

10x = 105 - 12x + 247 // Add 12x & combine like terms

10x + 12x = 352

22x = 352 //Divide 22

x = 352/22

x = 16

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3 years ago
A coin is tossed four times What is the probability of getting four heads? (1 mark) a) b) What is the probability of getting exa
BlackZzzverrR [31]
<h2>Answer:</h2>

1. A coin is tossed four times. What is the probability of getting four heads?

Each toss has a 1/2 chance of getting a head.

So the chance of getting all four heads can be calculated as :

1/2\times1/2\times1/2\times1/2=1/16

2. A coin is tossed four times. What is the probability of getting two heads?

Each toss can have 2 results, so 4 flips will have 2^{4} or 16 results.

Getting two heads means getting two tails also. So, we can get the number of times two heads come = \frac{4!}{2!2!} = 6

We can write the groups like - {HHTT,HTHT,HTTH,THHT,THTH,TTHH}

So, the required probability is : 6/16 or 3/8.

3. Not getting two heads means getting 3 tails and 1 head or all tails.

Probability of having all tails = 1/2\times1/2\times1/2\times1/2=1/16

Probability of one head(1st trial) and three tails = 1/16

Probability of one head (2nd trial) and three tails (the 1st, 3rd and 4th trials) = 1/16

Probability of one head (3rd trial) and three tails (the 1st, 2nd and 4th trials) = 1/16

Probability of one head (4th trial) and three tails (the 1st, 2nd and 3rd trials) = 1/16

So, the total probability showing only one or none head and at least three tails = 1/16+1/16+1/16+1/16+1/16=5/16

6 0
3 years ago
You have just opened a new dance club, Swing Haven, but are unsure of how high to set the cover charge (entrance fee). One week
bonufazy [111]

Answer:

a) The demand function is

q(p) = -4 p + 107

b) The nightly revenue is

R(p) = -4 p^2 + 107 p

c) The profit function is

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d) The entrance fees that allow Swing Haven to break even are between 10.03 and 23.41 dollars per guest.

Step-by-step explanation:

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Since the demand takes the value 79 in 7, then

q(p) = -4 (p-7) + 79 = -4 p + 107

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d) Lets find out the zeros and positive interval of P. Since P is a quadratic function with negative main coefficient, then it should have a maximum at the vertex, and between the roots (if any), the function should be positive. Therefore, we just need to find the zeros of P

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Therefore, the entrance fees that allow Swing Haven to break even are between 10.03 and 23.41 dollars per guest.

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Answer:

The correct answer is D

Step-by-step explanation:

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