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3 years ago

How many 16 are in 15 over 16

Mathematics

1 answer:

Virty [35]3 years ago

5 0

Answer:

the answer is 15

Step-by-step explanation:

So the answer is 15 because, 15 times of one-sixteenths, or in other words 15 sixteenths

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The table below shows the number of cameras made when an assembly line runs at a constant rate for a certain number of hours. Nu

jeka57 [31]

Computing the rate we get:

$\frac{300}{10}\frac{cameras}{\text{hour}}=30\frac{cameras}{\text{hour}}$

Then, when the assembly line runs at the same rate for 24 hours they will produce:

$24\text{hour}\cdot30\frac{cameras}{\text{hour}}=720\text{ cameras}$

Answer: Option C) 720.

7 0

1 year ago

Simplify the expression (7a5b6)4 . Please help

8_murik_8 [283]

Answer:

28a 20b 24

Step-by-step explanation:

3 0

3 years ago

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0.34 times 10 with an exponet 3

STALIN [3.7K]

Answer: 340

Step-by-step explanation:

Because if you multiply 0.34x 10 to the 3rd power you get 340

Hope This helped :))

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3 years ago

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Lim x--> 0 (e^x(sinx)(tax))/x^2

Tom [10]

Make use of the known limit,

$\displaystyle\lim_{x\to0}\frac{\sin x}x=1$

We have

$\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)$

since $\tan x=\dfrac{\sin x}{\cos x}$ , and the limit of a product is the same as the product of limits.

$\dfrac{e^x}{\cos x}$ is continuous at $x=0$ , and $\dfrac{e^0}{\cos 0}=1$ . The remaining limit is also 1, since

$\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1$

so the overall limit is 1.

4 0

3 years ago

First Person = Brainliest.

NeX [460]

Answer:

1080

___ rode a plane for 5^2 miles on a flight to ___. She then took a flight to ___ which was 5^4 miles. How much further did she fly on the second flight?

you can decide where she went and what her name was.

Step-by-step explanation:

6^3 = 213

6^4 = 1296

1296 - 216 = 1080

4 0

3 years ago

Read 2 more answers