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Goryan [66]
3 years ago
13

Anyone wanna help with my geometry?

Mathematics
1 answer:
monitta3 years ago
4 0

Answer:

I had that problem a while ago I’ll see if I can find the answer again

Step-by-step explanation:

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A driver driving a business trip of 240 miles would have reached his destination if he'd been able to drive 12 mph faster than h
mariarad [96]

The average speed of his trip is = 12 mile/ hour

The total distance covered by the driver = 240 miles

The rate at which he traveled = 12 miles per hour

Therefore, the time he used to cover his distance

= 240/12

= 20 hrs

But average speed = distance/ time

= 240/ 20

= 12 miles/ hour

Therefore, the average speed of his trip is = 12 mile/ hour

Learn more here:

brainly.com/question/11753352

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2 years ago
Does anyone know how to directly ask a tutor a question? It’s like the option to is gone. Answer asap please!
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Answer:

Just find the button to ask a question. Search around for it.

Step-by-step explanation:

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3 years ago
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Subtract 1/6a+3 from 1/3a−5 .
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Answer:

1/6a - 8 <-

Step-by-step explanation:

6 0
4 years ago
*15pts* Suppose a model of the Queen Mary is 17 inches in length. The actual length of the Queen Mary is 1020 feet. What is the
kiruha [24]
I think Queen Mary model 60 feet
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3 years ago
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Suppose that a storm front is traveling at 33 mph. When the storm is 13 miles away a storm chasing van starts pursuing an averag
kramer

Answer:

= 15mins 18 seconds. The storm chaser van drove 13.53 miles to catch up with the storm which obviously has moved less than 0.53 miles as it was same time but multiplied below by 0.5 per minute as speed per minute is 0.5 for the storm. See right at the end the storm only moved 1.11 mile.

Step-by-step explanation:

We count in 1 minutes

54 mph = 54/60 = 0.9 miles per minute

Storm = 13 m +  1 minute  is;

33/60 = 0.55 miles = 11/20

M = (16 7/10 * 9/10x) = ( 3 7/10 * 11/20y ) +13

M = 15 3/10x = ( 407/200y +13)       (407/200 = y starting value +13)

M = 15 3/10x =  15 3/10 = 16 7/10x (the same as 16 7/10* 9/10 for x)

M = 15 3/10 x = 15 3/10  = 15.03    

M = 16 7/10x  / 9/10y                      (is also the same as 186/1000)

X = 185⁄1000 = 37⁄200xy x 16 7/10  (as starting value)

7/10 of 60 = 42 minutes

3/10 of 60 = 18 minutes

x = 15 mins 18 seconds.

y = 15 mins  18 seconds.

as 0.005 left over for y 3/10 was actually 15.035 gives us 0.005 of 60 can not be rounded up to a second.

However as we started with 16mins and 7/10 we can see that we multiplied by 9/10 so when we divide 16 7/10 by 9/10 we find  185⁄1000 = 37⁄200

To equal the mileage of the storm of where we multiplied 3 7/10 by 17/10

= 37/200 just the same

We added 13 miles of the storm to find each was multiplied by the larger x sum 9/10 and y was multiplied  

As 35/200 + 13 =  

13 37/200  

37/200 of 60 = 11.1 = 11.06 minutes which is

= 15.04 % more for y as 13 + 2 mins + 06 seconds = 15.06 = 15.035

The percentage looks the same but valued different as 2 of 13 as a percentage is multiplied as 13 x 15.04%  to equal the 2 of 15 miles as 15.04%.

To find how many miles we go back and see 15.035 = 15 7/200

Then we multiply this by 0.9 miles for the storm van

= 15 7/200 x 0.9 = 13.5315 = 13.53 miles

For the storm itself we can prove 0.53  increase of mileage

417/200 x 0.53 = 1.10505 = 1.11 miles. rounded up

5 0
4 years ago
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