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Agata [3.3K]
3 years ago
5

Can someone please help me with this problem? An explanation would be great, but it can be short. Thank you!!

Mathematics
1 answer:
ss7ja [257]3 years ago
7 0

We are given two points: (4, -8) and (8, 5)

General equation of a line: y = mx + c

First find m (the gradient). There is a formula for this: (change in y)/(change in x) = gradient

(5 - -8) / (8 - 4) = (13) / (4) = 3.25 = m

y = 3.25x + c

Now we need to find c (the y-intercept; the value of y when x=0).

Substitute in any one of the coordinates - let's use (8, 5)

(5) = 3.25(8) + c

(5) = 26 + c

c = -21

The equation of the line: y = 3.25x - 21


I think that this answer is correct - sorry if it seems rushed.

Hope this answer helps :)

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Step-by-step explanation:

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I came up the answer as 57. I will attach my note, can you check?
ololo11 [35]

BC=19

Explanation

Step 1

ABE

triangle ABE is rigth triangle, then let

\begin{gathered} Angle=60 \\ adjacentside=BE \\ opposit\text{ side(the one in front of the angle)= AB=}\frac{19\sqrt[]{6}}{4} \end{gathered}

so, we need a function that relates, angle, adjancent side and opposite side

\tan \theta=\frac{opposite\text{ side}}{\text{adjacent side}}

replace

\begin{gathered} \tan \theta=\frac{opposite\text{ side}}{\text{adjacent side}} \\ \tan 60=\frac{AB}{\text{BE}} \\ \text{cross multiply} \\ \text{BE}\cdot\tan \text{ 60=AB} \\ \text{divide both sides by tan 60} \\ \frac{\text{BE}\cdot\tan\text{ 60}}{\tan\text{ 60}}=\frac{\text{AB}}{\tan\text{ 60}} \\ BE=\frac{\text{AB}}{\tan\text{ 60}} \\ \text{if AB=}\frac{19\sqrt[]{6}}{4} \\ BE=\frac{\frac{19\sqrt[]{6}}{4}}{\sqrt[]{3}} \\ BE=\frac{19\sqrt[]{6}}{4\sqrt[]{3}} \end{gathered}

Step 2

BED

again, we have a rigth triangle,then let

\begin{gathered} \text{Hypotenuse}=BD \\ \text{adjacent side= BE=6.71} \\ \text{angle}=\text{ 45} \end{gathered}

so, we need a function that relates; angle, hypotenuse and adjacent side

\cos \theta=\frac{adjacent\text{ side}}{\text{hypotenuse}}

replace.

\begin{gathered} \cos \theta=\frac{adjacent\text{ side}}{\text{hypotenuse}} \\ \cos 45=\frac{6.71}{\text{BD}} \\ BD=\frac{6.71}{\cos \text{ 45}} \\ BD=\frac{\frac{19\sqrt[]{6}}{4\sqrt[]{3}}}{\frac{\sqrt[]{2}}{2}} \\ BD=\frac{38\sqrt[]{6}}{4\sqrt[]{6}} \\ BD=\frac{38}{4} \end{gathered}

Step 3

finally BDE

let

angle=30

opposite side= BD

use sin function

\begin{gathered} \sin \theta=\frac{opposite\text{ side}}{\text{hypotenuse}} \\ \text{replace} \\ \sin \text{ 30=}\frac{BD}{BC} \\ BC\cdot\sin 30=BD \\ BC=\frac{BD}{\sin \text{ 30}} \\ BC=\frac{\frac{38}{4}}{\frac{1}{2}} \\ BC=\frac{76}{4}=19 \\ BC=19 \end{gathered}

so, the answer is 19

I hop

4 0
1 year ago
If you flip a coin 3 times what is the probability of getting at least 2 tails
elixir [45]
If you flipped a coin 3 times:{

Total number of possible outcomes = 2³ = 8

Total number of outcomes with at least 2 tails = 4
{HTT , THT, TTH, TTT}

P(at least 2 tails ) = 4/8 = 1/2

Answer: 1/2




4 0
3 years ago
Read 2 more answers
NEED HELP ASAP!!!! GIVING BRAINLIEST+ 30 POINTS TO WHOEVER CAN ANSWER THESE TWO QUESTIONS THE BEST!!!
Rom4ik [11]
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Because 5*3=15 and the 4 on the bottom remains
2-is 10/8
Again do the same method of multiplying the top(numerator) by the whole number so 2/1*5/8=10/8
Or 2*5=10
And 1*8=8
7 0
2 years ago
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