PV=nRT so if T increases P increases because V is constant in your closed system.
the pressure increases
Answer:
Worst: That was the worst day of my life.
Confident : I am so confident that I will pass my exams with high grades.
Anxious : She was extremely anxious about her exams.
Bandage : Bandage the foot so that the leg is supported.
Crutches: The man with crutches is my best friend.
Answer:
(a) Please find attached a diagram of the model representing the ratio of the panel to the amount saved on her electric bill
(b) The reduced fraction of the ratio of panels to money saved is
Step-by-step explanation:
The given parameter from the Sunny Solar Company, on the cost savings from the use of solar panels is as follows;
The amount Mrs. Jolley saves on her electricity bill for every 2 solar panels = $60
(a) A model visually representing the ratio of the panels to the amount saved on her electric bill is created using Microsoft Visio as shown in th attached drawing
(b) The ratio of panels to money saved is given as follows;
Therefore the reduced fraction of the ratio of panels to money saved is given as follows;
Step-by-step explanation:
have a good day
Answer:
1120
Mutiply the numbers then add
Answer:
WU = (14√13)/13 ≈ 6.6564
Step-by-step explanation:
Call the incenter of ∆KWU point A. Call the center of circle ω2 point B.
Then ∠KWA has half the measure of arc WA. ∠AWU is congruent to ∠KWA, so also has half the arc measure. That is, ∠KWU has the same measure as arc WA and ∠KBW.
KB is a perpendicular bisector of chord WU, so ∆KWB is a right triangle, of which WU is twice the altitude to base KB.
The length of KB can be found several ways. One of them is to use the Pythagorean theorem:
KB² = KW² +WB² = 4² +6² = 52
KB = √52 = 2√13
The area of triangle KWB is ...
area ∆KWB = (1/2)KW·WB = (1/2)(4)(6) = 12 . . . . square units
Using KB as the base in the area calculation, we have ...
area ∆KWB = (1/2)(KB)(WU/2)
12 = KB·WU/4
WU = 48/KB = 48/(2√13) = 24/√13
WU = (24√13)/13 ≈ 6.6564