Answer: 24
A hyperbola is the locus of a point in a plane which moves in the plane in such a way that the ratio of its distance from a fixed point in the same plane to its distance from a fixed line is always constant, which is always greater than unity.
the fixed point is called the focus and the fixed line is directrix and the ratio is the eccentricity.
The general equation for the vertical hyperbola is
[ (y-k)^2 / a^2 ] – [ (x-h)^2 / b^2 ] = 1
The conjugate axis of the vertical hyperbola is y = k
Length of the conjugate axis = 2b
According to the question k = 2, h = -1, a = 4, b = 12
Length of the conjugate axis = 2b = 2 * 12 = 24
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Answer:
Leg1 = 9 and leg2 = 12
Step-by-step explanation:
<u>Points to remember</u>
<u>Pythagorean theorem</u>
Hypotenuse² = Base² + Height²
<u>To find the length of each leg</u>
It is given that, hypotenuse = 15 feet
Let base = x the height = x +3
By using Pythagorean theorem we can write,
Hypotenuse² = Base² + Height²
15² = x² + (x + 3)²
225 = x² + x² + 6x + 9
2x² + 6x + 216 = 0
x² + 3x + 108 = 0
By solving we get x = 9 and x -12
Therefore one leg = 9 and other leg = 9 + 3 = 12
Simplify square roots
find all the prime factors of the radicand
and group them in pairs
any factor that appears in a pair can be pulled out in front of the radical sign once for ever group of two that can be made.
Hope that help sorry if it doesn't make sense.. :( <3
Answer:
x= 2 5/6
Step-by-step explanation:
1/3= 2/6
2 1/2= 2 3/6
2/6+ 2 3/6= 2 5/6
Hope this helps! :)