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2 years ago

A and B share the cost in a ratio of 3:2 A pays 125£ how much does b pay???

2 answers:

8 0

Let the common multiple be x
3x : 2x 
3x = 125 
x = 125/3 

So, B pays 2x = 2 × 125/3 = £250/3

Drupady [299]2 years ago

3 0

3:2
3+2=5
125 divided by 5
=15

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Find the length of EF

Lisa [10]

Answer:

Step-by-step explanation:

1. First, we need to set up an equation to find the value of x and then the length of EF.

2. We know that DG is equal to 33, so we can add all the three sections it's cut into altogether to get 33. Therefore, we get an equation of: $3x - 28 + 3x - 30 + x = 33$

3. (Solving for x)

Step 1: Simplify both sides of the equation.

$3x - 28 + 3x - 30 + x = 33$
$(3x+3x+x) + (-28-30)=33$
$7x - 58 = 33$

Step 2: Add 58 to both sides.

$7x - 58 + 58 = 33 + 58$
$7x = 91$

Step 3: Divide both sides by 7.

$\frac{7x}{7} = \frac{91}{7}$
$x = 13$

4. Now that we know x is equal to 13, we can plug that value in for the expression 3x - 30.

$3(13)-30$
$39 - 30$
$9$

Therefore, the length of EF is 9.

7 0

3 years ago

Which of the following points lies on the graph of the function y = 8x?

nignag [31]

Y = 8^x
For (0, 1): 1 ≠ 8^0 = 1
For (8, 1): 1 ≠ 8^8 = 16,777,216
For (2, 64): 64 = 8^2
For (0, 8): 8 ≠ 8^0 = 1

Therefore, option 3, (2, 64) is the correct answer.

8 0

2 years ago

Read 2 more answers

Please help me out!!!!

Kobotan [32]

Answer:

All real numbers

Step-by-step explanation:

4(x+1) = 4x+4

Distribute

4x+4 = 4x+4

Subtract 4x from each side

4x+4-4x = 4x+4-4x

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This is always true so there are infinite solutions

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2 years ago

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What is the estimate of the sum of 6/10 + 7/12

aleksandr82 [10.1K]

71/60. You change the denominators(bottom numbers) to 60 because that is the smallest number that both 10 and 12 can go into. Then you just add.

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3 years ago

Can someone please help with this trig question?

atroni [7]

First we must understand how to write a logarithmic function:

$log_{b}a=x$

In the equation above, b is the base, x is the exponent, and a is the answer. These same variables can be rearranged to be expressed as an exponential equation as followed:

$b^x=a$

Next, we need to understand basic logarithm rules.

1. When a value is raised to a power, we can move the exponent to the front of the logarithm. Example:

log(a^2) = 2log(a)

2. When two variables are multiplied together, we can add the logarithms of the individual variables together. Example:

log(ab) = log(a) + log(b)

3. When a variable is divided by another variable, we can subtract the logarithms of the individual variables. Example:

log(a/b) = log(a) - log(b)

Now we can use these rules to solve the problem.

$log(r)=log( \sqrt[3]{ \frac{A^2B}{C} } )$

We can rewrite the cube root as:

$log(r) = log( (\frac{A^2B}{C})^ \frac{1}{3} )$

Now we can move the one-third to the front:

$log(r) = \frac{1}{3} log( \frac{A^2B}{C} )$

Now we can split up the logarithm:

$log(r) = \frac{1}{3} (log(A^2)+log(B)-log(C))$

Finally, we can move the exponent to the front of the log of A:

$log(r) = \frac{1}{3} (2log(A)+log(B)-log(C))$

Distribute the one-third to get the answer:

$log(r) = \frac{2}{3} log(A) + \frac{1}{3} log(B) - \frac{1}{3} log(C)$

The answer is (4).

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3 years ago