Question

If x^2 -8x=48 and x<0, what is the value of x+10?

Answer 1

Answer:

6

Step-by-step explanation:

To calculate x+10, we first need to find x. To do this, we can use the first equation.

We are given the equation:

$x^2-8x=48$

To solve for x, turn one side of the equation into 0 and solve. Therefore:

$x^2-8x=48\\x^2-8x-48=0\\(x-12)(x+4)=0\\x=-4, 12$

So, the possible values for x are -4 and 12.

However, we are also told that x<0. In other words, x must be negative. Thus, we can remove 12. That leaves us with: x=-4.

So:

$x+10\\(-4)+10\\=6$

Answer 2

X^2 -8x - 48 = 0
(x-12)(x+4) = 0
x=12, x=-4
Since x<0, x must be -4
Therefore, -4+10=6