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3 years ago

What is the greatest common factor (GCF) of 24 and 36? 4 12 2 6

Mathematics

2 answers:

jolli1 [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Tju [1.3M]3 years ago

5 0

the greatest common factor of 24 and 36 is 12

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The price of shares of Nadir Explorations Ltd. fell by 76% in the past year, to the current price of $0.45 per share. In dollars

Gemiola [76]

Answer:

$0.342 ; 34.2 cents

Step-by-step explanation:

Given that:

Share price fell by 76% in past year :

current price per share = $0.45

Drop in price of share in past year :

76% of current price

0.76 * $0.45

= $0.342

Price dropped by $0.342 per share

In cent, 0.342 * 100 = 34.2 cents

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3 years ago

The owner writes a line of best fit equation, shown below, to model the relationship between profit earned and month. y = 2,500x

Natali5045456 [20]

What is your question?

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3 years ago

Which statement is true ?

podryga [215]

Answer:

Step-by-step explanation:

plan 2 grows exponentially so it grows at a faster rate than plan 1, even though plan 1 starts with 100 members

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2 years ago

In an attempt to escape a desert island, a castaway builds a raft and sets out to sea. The wind shifts a great deal during the d

nikdorinn [45]

Answer:

R = 7,34 km

Ф = 63,43° north of east

Step-by-step explanation:

Let´s analyze each movement and find its perpendicular components. Then, we are going to add the components along the x and y axes to get the resultant and finally to calculate its magnitude and direction.

To determine the perpendicular components, we will use right triangles trigonometrics ratios.

Please see images for each displacement in attached file.

Displacement A: 2.50 km and 45° north of west

Ax= AcosФ = 2.50cos45° = 1.77 km (neg. direction)

Ay= AsenФ = 2.50sen45° = 1.77 km (pos. direction)

Displacement B: 4.70 km and 60° south of east

Bx= BcosФ = 4.70cos60° = 2,35 km (pos. direction)

By= BsenФ = 4.70sen60° = 4,07 km (neg. direction)

Displacement C: 1.30 km and 25° south of west

Cx= CcosФ = 1.30cos25° = 1,18 km (neg. direction)

Cy= CsenФ = 1.30sen25° = 0.55 km (neg. direction)

Displacement D: 5.10 km due east (0°)

Dx= DcosФ = 5.10 km (pos. direction)

Dy= DsenФ = 0 km

Displacement E: 1.70 km and 5° east of north

Ex= EsenФ = 1.70sen5° = 0,15 km (pos. direction)

Ey= EcosФ = 1.70cos5° = 1.69 km (pos. direction)

Displacement F: 7.20 km and 55° south of west

Fx= FcosФ = 7.20cos55° = 4.13 km (neg. direction)

Fy= FsenФ = 7.20sen55° = 5.90 km (neg. direction)

Displacement G: 2.80 km and 10° north of east

Gx= GcosФ = 2.80cos10° = 2.76 km (pos. direction)

Gy= GsenФ = 2.80sen10° = 0.49 km (pos. direction)

Now, we add the components along the x- and y- axis to find the components of the resultant (R):

Rx = Ax + Bx + Cx + Dx + Ex + Fx + Gx

Ry = Ay + By + Cy + Dy + Ey + Fy + Gy

Therefore,

Rx= (-1.77)+(2.35)+(-1.18)+(5.10)+(0.15)+(-4.13)+(2.76)

Ry= (1.77)+(-4.07)+(-0.55)+(0)+(1.69)+(-5.90)+(0.49)

Note: minus (-) symbol to negative directions

Rx = 3.28 km

Ry = - 6.57 km

Let´s use the Theorem of Pythagoras to find the magnitud ot the resultant:

$R = \sqrt{Rx^{2} +Ry^{2} }$

$R =\sqrt{(3.28)^{2}+(-6.57)^{2} }$

R = 7,34 km

To find the direction of the resultant:

tanФ = $\frac{Ry}{Rx}$

tanФ = $\frac{6.57}{3.28}$

tanФ = 2.00

Ф = tan-1 (2.00)

Ф = 63,43° north of east

Download pdf

3 0

4 years ago

What is the area of a sector in a circle with a 7 m. radius and a central angle of 100°?

Doss [256]

Answer:

42.74 m²

Step-by-step explanation:

full circle area = πr² = (3.14)(7²) = 153.86 m²

(100°/360°)(153.86 m²) = 42.74 m²

7 0

3 years ago

Read 2 more answers