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3 years ago

Which linear function show a direct variation

Mathematics

1 answer:

xz_007 [3.2K]3 years ago

6 0

Answer:

it should be answer choice c but im not positive

Step-by-step explanation:

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How would i solve this x+2/x+7=3/6

Ksivusya [100]

(x + 2)/(x + 7) = 3/6
6(x + 2) = 3(x + 7)
6x + 12 = 3x + 21
6x - 3x = 21 - 12
3x = 9
x = 9/3 = 3

7 0

4 years ago

Write an equivalent expression for (116)5.

Radda [10]

Answer:

580 is the answer i thik its helps u tqq

3 0

3 years ago

What is this equation 4(3+5)- 3.9*2<br> THIS ISN´T A DECIMAL ITS A MIDDLE DOT

vredina [299]

Answer:

The answer is letter 'J'

Step-by-step explanation:

4(3+5) - 3 x 9^2

4(8) - 3 x 9^2 ← 9 x 9 = 81

16 - 3 x 9^2

16 - 3 x 81

13 x 81

1,053

4 0

3 years ago

Suppose that the probability that a person will develop hypertension over a life time is 60%. Of 13 graduating students from the

Savatey [412]

Answer:

The mean number of the students who develop hypertension over a life time is 7.8.

Step-by-step explanation:

For each person, there are only two possible outcomes, either they will develop hypertension, or they will not. The probability of a person developing hypertension is independent of any other person, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

The expected value of the binomial distribution is:

$E(X) = np$

Suppose that the probability that a person will develop hypertension over a life time is 60%.

This means that $p = 0.6$

13 graduating students from the same college are selected at random.

This means that $n = 13$

Find the mean number of the students who develop hypertension over a life time

$E(X) = np = 13*0.6 = 7.8$

The mean number of the students who develop hypertension over a life time is 7.8.

5 0

3 years ago

Tan(y)+ cot(y)/csc(y)= sec(y) prove identity

ArbitrLikvidat [17]

[tan(y) + cot (y)]/csc (y)

tan (y) = sin (y)/cos (y)
cot (y) = cos (y)/sin (y)
csc (y) = 1/sin (y).
Now rewrite the expression with the equivalent values

[sin (y)/cos (y) + cos (y)/sin (y) ] / [1/sin (y)]

1st, let's work the Numerator only = [sin (y)/cos (y) + cos (y)].
= [(cos² (y) + sin² (y)]/ [cos (y).sin(y)]

or (cos² (y) + sin² (y) = 1, →Numerator = 1/[cos (y).sin(y)]

Denominator = csc (y) = [1/sin (y)], Then:

N/D = 1/[cos (y).sin(y)] / [1/sin (y)] = [1 x sin (y)]/ [cos (y).sin (y)] = 1/cos (y)

Or 1/cos (y) = sec (y) Q.E.D

4 0

4 years ago