Answer:
A = 54.8 - (1200/x) - 2x
Step-by-step explanation:
Given <em>x</em> the wide and <em>y</em> the height, we have
x*y = 50
⇒ y = 50/x
The area of the printed region is A = w*h
where
Wide: w = (x-2*1.2) = x-2.4
Height: h= (y-2*1) = y-2
then
A = (x-2.4)(y-2) = xy - 2.4y - 2x + 4.8 = 50 - 24*(50/x) - 2x + 4.8
⇒ A = 54.8 - (1200/x) - 2x
Angles XQL and MQR are congruent because they are vertical angles. So
209 - 13 <em>b</em> = 146 - 4 <em>b</em>
Solve for <em>b</em> :
209 - 13 <em>b</em> = 146 - 4 <em>b</em>
209 - 146 = 13 <em>b</em> - 4<em> b</em>
63 = 9 <em>b</em>
<em>b</em> = 63/9 = 7
Then the measure of angle XQL is
(209 - 13*7)º = 118º

Length of the room is 5 m and width is 5 + 2 = 7 m.
Hope this helps.
r3t40