Answer:
108 ft squared.
Step-by-step explanation:
The figure is made up of a triangle and a square.
The area of a triangle is (1/2)*b*h. The height of the triangle is 6 ft and the base is 9 ft, since the triangle shares a side with the square. Since all sides of the square are equal we know that the line that is shared by the triangle and the square must also be 9ft.
Area of the triangle: (1/2)*9*h = 27 Square feet
To find the area of a square you multiply b*h or sides squared
Area of the square: 9*9 = 81 squared feet
<em>Finally, you have to add the two areas together to get the overall area.</em>
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So, 27 Feet Squared + 81 Feet Squared = 108 Feet Squared
Hello,
Let's to remember,
To the perfect square:
X^2 +12x = -6
We would have to add 6^2
Because,
X^2 + 2.(6X) = -6
As (x+k) = x^2 +2xk +k
And,
2xk = 2.6x
xk = 6x
K = 6
Then,
(X+k)^2 = x^2 + 2xk+k^2
= x^2+2.x.6+6^2
= x^2+6x+36
We would to add 36, and would stay:
X^2 + 6X = -6
x^2 +6x + 36 = -6 +36
X^2 +2.6x +6^2 = 30
(X+6)^2 = 30
Answer is the letter A)
Answer:
x=6,y= 7
Step-by-step explanation:
-6x +7y= 13
-6x+8y=20
-y = -7
divide through by -1
y =7
sub y= 7 in equation 1
then x= 6
Answer:
<h2>
cos (α + β) = 0.9196</h2>
Step-by-step explanation:
Given sin α = –4∕5 and sin β = 1∕2
To get α from sin α = –4∕5,
α = arcsin(-4/5)
α = arcsin (-0.8)
α = -53.13°
If angle α is in quadrant III, then α = 180+53.13 = 233.13° (sin is negative in the 3rd quadrant)
Similarly for sin β = 1∕2
β = arcsin(1/2)
β = arcsin(0.5)
β = 30°
Since β is in quadrant II, β = 180-30 = 150°
To find cos (α + β). where α = 233.13° and β = 30°
cos (α + β)= cos (233.13 + 150)
= cos 383.13°
cos (α + β) = 0.9196
