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Nimfa-mama [501]
4 years ago
13

What is 15456415 times 45415

Mathematics
1 answer:
masha68 [24]4 years ago
4 0

Answer: 701953087225 is the answer

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Simplifying an Expression with the Numerator and the Denominator Raised to a Power
slamgirl [31]

Answer:

The answer to your question is    the second option     \frac{1}{x^{48}y^{36}z^{6}}

Step-by-step explanation:

Expression

                       [\frac{(x^{2}y^{3})^{-2}}{(x^{6}y^{3}z)^{2}}]^{3}

Process

1.- Divide the fraction in numerator and denominator

a) Numerator  

 [(x²y³)⁻²]³ = (x⁻⁴y⁻⁶)³ = x⁻¹²y⁻¹⁸

b) Denominator

 [(x⁶y³z)²]²= (x¹²y⁶z²)³ = x³⁶y¹⁸z⁶

2.- Simplify like terms

a) x⁻¹²x⁻³⁶ = x⁻⁴⁸

b) y⁻¹⁸y⁻¹⁸= y⁻³⁶

c) z⁻⁶

3.- Write the fraction

        \frac{1}{x^{48}y^{36}z^{6}}

6 0
3 years ago
Identity the two rational numbers
Leno4ka [110]
B and D are both rational.

A rational number is a number that can be represented as a ratio fo two integers.

-7/3 is rational because both -7 and 3 are integers. 2.777... equals 25/9. 25 and 9 are both rational numbers.
3 0
4 years ago
I need help with these problems ASAP
svetoff [14.1K]
3 is $16! Hope I helped
8 0
4 years ago
Read 2 more answers
An equation is written where the sum of two 3-digit numbers is a 3-digit number N. Each digit, 1 through 9, is used exactly once
Sindrei [870]
We can start with:
x + y = N
where
x is the first 3 digit number
y is the second 3 digit number

In order to get the maximum value of N, the digits used must 9,8,7,6,5,4
To maximize, 9 and 8 must be added. This can only happen if 9 is the first digit of the first number and 8 is the first digit of the second number. The same idea is applied to the other digits. So
x must be 975 and
y must be 864
N = 975 + 864 = 1839
7 0
3 years ago
Read 2 more answers
Find the upper 20%of the weight?
meriva

Answer:

The upper 20% of the weighs are weights of at least X, which is X = 0.84\sigma + \mu, in which \sigma is the standard deviation of all weights and \mu is the mean.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Upper 20% of weights:

The upper 20% of the weighs are weighs of at least X, which is found when Z has a p-value of 0.8. So X when Z = 0.84. Then

Z = \frac{X - \mu}{\sigma}

0.84 = \frac{X - \mu}{\sigma}

X = 0.84\sigma + \mu

The upper 20% of the weighs are weights of at least X, which is X = 0.84\sigma + \mu, in which \sigma is the standard deviation of all weights and \mu is the mean.

6 0
3 years ago
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