Answer:
Look below
Step-by-step explanation:
So I will use an example to try and show you how to do this.
If we have 
, we know that we don't have like denominators. We can change this by finding one. All we need to do is multiply our denominators. So in our example, that would be 
. Our new denominator would be 6. So now we would have 
which isn't the same as our old equation. That is because we haven't multiplied our top numbers yet. To do this, we need to multiply the top number by the opposite denominator like so, 
.
So our first fraction was
We then multiplied the whole fraction by the opposite denominator
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The slope-intercept form of the linear function is y = m x + b , where m is the slope and b is y-intercept.
Here we have: y = 3 x - 3
a ) When y = 0
0 = 3 x - 3
- 3 x = - 3
x = ( - 3 ) : ( - 3 )
x = 1
When x = 0
y = 3 * 0 - 3
y = - 3
So x - intercept is ( 1, 0 ) and y-intercept is ( 0, - 3 ).
b ) The slope:
m = ( y2 - y1) / ( x2 - x1 ) =
= ( - 3 - 3 ) / ( 5- 7 ) = ( - 6 ) /( - 2 ) = 6 / 2 = 3
Answer: The slope m = 3 .
Answer:
5 terms
Step-by-step explanation:
nth term of the sequence =n^2 + 20
an= n^2 + 20
1st term when n= 1
1^2 + 20= 20
2nd term n= 2
2^2 + 20=24
3rd term when n= 3
3^2 + 20= 29
4th term when n= 4
4^2 + 20= 36
5th term when n= 5
5^2 + 20 =45
6th term when n= 6
6^2 + 20=56
Hence, terms in the sequence are less than 50 are first 5 terms
Answer:
Infinite many solutions. Any x-value can satisfy the equation.
Step-by-step explanation:
Let's work on simplifying the equation a little to investigate which x-values satisfy it. Start by combining like terms on the left side (6x +4x=10x),
then distribute the factor "10" into the binomial (x+10), obtaining 10x +30.
Now we have the same expression on the left and the right of the equal sign:
10x +30=10x+30. We may subtract 30 from both sides, and obtain 10x=10x, and at this point divide by 10 both sides, and we obtain: x=x
The process is shown below.
x=x is an equation that is verified by absolutely ANY x value on the number line, and there are infinite x-values in the number line.
Therefore there are infinite many solutions to this equation (any x-value will satisfy it).
