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Katyanochek1 [597]
3 years ago
9

B^-3 = 1/64 what equals b

Mathematics
1 answer:
s2008m [1.1K]3 years ago
5 0
64=2*2*2*2*2*2=2⁶


B⁻³=1/64
1/B³=1/2⁶
B³=2⁶
B=∛2⁶=2⁶/³=2²=4

Answer: B=4
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-3x - 8 + 6x = 7 wat is the answer
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3x-8+6x=7
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9x=15
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7 0
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Solve this pls thank you
Nana76 [90]

Answer:21

Step-by-step explanation:9+10=21

5 0
2 years ago
Please help!!!<br> Which expression is equivalent to (3m^-1n^2)^4/(2m^-2n)^3
Elza [17]
\text{Use:}\\\\(a\cdot b)^n=a^nb^n\\\\(a^n)^m=a^{n\cdot m}\\\\\dfrac{a^n}{a^m}=a^{n-m}

\dfrac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}=\dfrac{3^4(m^{-1})^4(n^2)^4}{2^3(m^{-2})^3n^3}=\dfrac{81m^{-4}n^8}{8m^{-6}n^3}\\\\=10.125m^{-4-(-6)}n^{8-3}=10.125m^2n^5
7 0
3 years ago
Read 2 more answers
The circumference of a circle exceeds the radius by 74 cm. Find the radius of the circle.​
saw5 [17]

Answer:

14 cm.

Step-by-step explanation:

Let the radius of the circle = r cm.

Then circumference of circle = 2 π r.

Since circumference exceeds the radius by 74 cm

Therefore, according to the question,

\sf \:2 π r = r+ 74

\sf \: =   > 2 \times  \frac{22}{7}  \times r =  r \:  + 74

\sf \: =  >  \frac{44r}{7}  -r  = 74

\sf \:  =  > \frac{44r - 7r}{7}  = 74

\sf \: =  >  \frac{37r}{7}  = 74

\sf \: =  > r =  \frac{7 \times 74}{37}

\sf \: =  >  r = 14

  • Hence, the radius of the circle is 14 cm.

________________________________

3 0
2 years ago
Read 2 more answers
A bottling company uses a filling machine to fill plastic bottles with cola. The bottles are supposed to contain 300 milliliters
PilotLPTM [1.2K]

Answer:

e. 0.0072

Step-by-step explanation:

We are given that a bottling company uses a filling machine to fill plastic bottles with cola. And the contents vary according to a Normal distribution with Mean, μ = 298 ml and Standard deviation, σ = 3 ml .

 Let    Z = \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)  where, Xbar = mean contents of six randomly

                                                                     selected bottles

                                                          n = sample size i.e. 6    

So, Probability that the mean contents of six randomly selected bottles is less than 295 ml is given by, P(Xbar < 295)

 P(Xbar < 295) = P( \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } < \frac{295 - 298}{\frac{3}{\sqrt{6} } } ) = P(Z < -2.45) = P(Z > 2.45)

Now, using z% score table we find that P(Z > 2.45) = 0.00715 ≈ 0.0072 .

Therefore, option e is correct .

7 0
3 years ago
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