Animals that have gills when found and lungs as adults?

How does the haemoglobin provide the body with energy ?

anzhelika [568]

Answer:

Hemoglobin transfers oxygen from the lung to the muscles, brain, and other organs, and also helps the body to convert carbohydrates and fat into energy.

5 0

3 years ago

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In _______________________ both alleles are fully expressed in the individual.

Tju [1.3M]

Answer: Codominence

Explanation:

Codominence is a condition in which two alleles of the same gene are expressed equally. Both alleles are capable of exerting their effects on the organism. Thus instead of expression of one trait both traits are expressed.

7 0

3 years ago

PLEASE HELP ME!!!!<br> IT IS FOR BIOLOGY!!!

g100num [7]

Answer:

C.

Explanation:

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3 years ago

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masteringbio JFor each of the studies described below, indicate if it is hypothesis driven and whether the scientist is employin

juin [17]

Incomplete question. The remaining part of the question read;

Words in the left column:

Yes
No
Observational
Manipulative

1. A physiologist incubates eggs in the lab at a range of temperatures to see what temperatures produce males and what temperatures produce females.

2. A biologist predicts that shade might influence ground temperature, and therefore turtle sex ratios. He records the sex ratio of turtle hatchlings in shaded and unshaded regions

3. An ecologist predicts turtles grow larger when no predators are around. She places turtles in an experimental pond system where half the ponds have predators and half the ponds have had the predators removed.

4. A climatologist predicts that concentration of CO2 in a city will be negatively correlated with the amount of wind in that city. He collects data and looks at the amount of CO2 in a city as a function of the wind speed in the city.

5. A sociologist conducts a survey in Hawaii to describe people's attitudes about global climate change.

6. A scientist determines the average wind speed, and variation in the amount of wind, in a number of locations to see which locations would be most suitable for wind turbines

<u>Answer/Explanation:</u>

1. <u>Hypothesis-driven?</u> Yes!

<u>Observational or Manipulative?</u> Observational.

We can make this conclusion here that the physiologists' research is hypothesis-driven since we are told he wanted to <em>"see what temperatures produce males and what temperatures produce females." </em>In other words, he wanted to know whether the temperature used in incubators can influence the sex of an egg by means of observation.

2. <u>Hypothesis-driven?</u> Yes!

<u>Observational or Manipulative?</u> Observation.

3. <u>Hypothesis-driven?</u> Yes!

<u>Observational or Manipulative?</u> Manipulative.

We can make the conclusion that is the ecologist used the manipulative method in her research since she decided to place the turtles in two different types of ponds; one where half the ponds have predators while in the other the pond the predators have been removed. In other words, she manipulated the independent variables.

4. <u>Hypothesis-driven?</u> Yes!

<u>Observational or Manipulative?</u> Observational.

Note, the use of the word, "predicts" in most instances underscores the tone of hypothesis-driven research, hence we can say Yes! And remember, we are told the researcher "collects data", meaning he is merely observing differences that occur naturally.

5. <u>Hypothesis-driven?</u> No!

<u>Observational or Manipulative?</u> Observational.

<u>6. Hypothesis-driven?</u> No!

<u>Observational or Manipulative?</u> Observational.

5 0

3 years ago

In Drosophila, the genes for withered wings (whd), smooth abdomen (sm) and speck body (sp) are located on chromosome 2 and are s

lesya692 [45]

Answer:

A) 47; B) 33; C) 272; D) 122

Explanation:

The three genes are linked.

The female with withered wings and a smooth abdomen has the genotype whd sm sp+/whd sm sp+.

The male with a speck body has the genotype whd+ sm+ sp/whd+ sm+ sp.

Both individuals are homozygous for all genes, so each of them only produces one type of gamete. The resulting F1 therefore has the genotype whd sm sp+/ whd+ sm+ sp, heterozygous for all genes and with a wild-type phenotype.

The females of the F1 were mated with homozygous recessive males (test cross): whd sm sp/whd sm sp.

If we assume interference is 0, the probability of crossing over happening between the genes whd and sm is independent from the probability of crossing over happening between sm and sp.

The distance = frequency of recombination × 100, so the frequency of recombination (RF) between genes whd and sm is 0.305 and the RF between genes sm and sp is 0.155.

<u>The expected double crossover progeny among the 1000 offspring will be:</u>

RF whd-sm × RF sm-sp × 1000 =

0.305 × 0.155 × 1000 = 47 individuals will be double crossover.

Interference is 0.3

The interference is calculated as 1- coefficient of coincidence (cc).

cc = observed double crossover/expected double crossover

Therefore:

I = 1 - cc

cc = 1 - I

Observed DCO / 47 = 0.7

Observed DCO = 0.7 × 47

Observed DCO ≅ 33

The parental gametes are whd sm sp+ and whd+ sm+ sp (the genotype of the F1 female is known).

Looking at them and at the gene map we can tell that the gametes that give rise to withered wings, speck body (whd sm+ sp) and smooth abdomen (whd+ sm sp+) phenotypes are the result of recombination occurring between genes whd and sm.

To calculate the expected number of individuals with those phenotypes among the 1000 progeny we need to determine the frequency of recombination between the genes whd and sm considering there's interference.

The distance whd-sm = RF x 100

The recombination frequency is the sum of the single crossover between whd and sm and the double crossovers.

The frequency of DCO is 33/1000=0.033.

Distance whd-sm/ 100 = SCOwhd-sm + DCO

0.305 - 0.033 = SCO whd-sm

<u>Frequency of SCO whd-sm= 0.272</u>

And the expected number of individuals with those phenotypes will be 0.272 x 1000 = 272.

The gametes that originate the phenotypes withered wings, speck body, smooth abdomen (whd sm sp) and wild type (whd+ sm+ sp+) are the result of recombination between genes sm and sp.

Distance sm-sp/ 100 = SCOsm-sp + DCO

0.155 - 0.033 = SCOsm-sp

<u>Frequency of SCO sm-sp= 0.122</u>

And the expected number of individuals with those phenotypes will be 0.122 x 1000 = 122.

6 0

4 years ago