The library is in the 4th quadrant (+x,-y)
So the English class must have a positive x and a negative y
(4,-5) is the only point that fits
Answer:
D, E &F
Step-by-step explanation:
Lets's go down the list and evaluate each choice
A. (3^8) / (3^4) = 3^ (8-4) = 3^4 (≠ 3^2)
B. 6²/2 = (2 x 3)²/2 = (2²·3²)/2 = 4·3²/2 = 2.3² (≠ 3^2)
C. (3^5) ·(3^3) = 3^ (5+3) = 3^8 (≠ 3^2)
D 3·3 = 3^2 (Answer)
E. (3^12) / (3^10) = 3^ (12 -10) = 3^2 (Answer)
F. (3^-3) / (3^-5) = 3^ [ -3 -(-5) ] = 3^ (-3 + 5) = 3^2 (Answer)
since AC=1/2AB=6 THEREFORE C is the midpoint ofAB
Answer:
1/8*100%
= 12.5%
Step-by-step explanation:
Answer:
1/2(x²) square units
Step-by-step explanation
From the question,
Area of a Square(A) = L²
A = L²................. Equation 1
Where L = Lenght of the square
If the diagonal of the square is x,
Using pythagoras theorem,
a² = b²+c².................. Equation 2
Wherer a = x, b = c= L
Therefore,
x² = L²+L²
x² = 2L²
L² = x²/2
L = √(x²/2)
Substitute the value of L into equation 1
A = [√(x²/2)]²
A = x²/2 square unit.
A = 1/2(x²) square unit.
The right option is 1/2(x²) square units
