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Furkat [3]
3 years ago
12

David wants to make a box plot showing histeam's points for the year. The median score was 7, first quartile was 4, and third qu

artile was 10. The minimum was 2 and the maximum was 20. Explain how David can draw the box plot.

Mathematics
1 answer:
vichka [17]3 years ago
8 0
A dot above 7, 4, 10, 2, and 20. Draw a box around the median, first quartile, and and the third quartile. Then connect the box to the minimum and maximum by drawing a line. Should look like this:

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SOMEONE ANSWER QUICK!!
Thepotemich [5.8K]

Answer:

3/4 pizza is left. If you want an explanation, ask me ;>

8 0
2 years ago
Read 2 more answers
I need help, the options are: Corresponding Angles, Vertical Angles, Alternate interior angles, linear pair, alternate exterior
stiks02 [169]

Answer:

✔️ <1 and <3 => Vertical angles

✔️<2 and <6 => alternate exterior angles

✔️<2 and <4 => corresponding angles

✔️<3 and <7 => alternate interior angles.

✔️<4 and <3 => consecutive interior angles.

✔️<7 and <6 => linear pair angles.

Step-by-step explanation:

✔️ <1 and <3 are opposite angles formed when two straight lines intersect. They both share the same vertex. Thus, they are vertical angles, which are congruent to each other.

<1 and <3 are vertical angles.

✔️<2 and <6 are alternate exterior angles.

<2 and <6 both lie outside the straight lines cut across by the transversal, and they also lie in the side of the transversal alternating each other

✔️<2 and <4 are corresponding angles.

They both take the same position on the same side of the transversal.

✔️<3 and <7 are alternate interior angles.

They are alternating angles along the transversal that are located just within the two lines intersected by the transversal.

✔️<4 and <3 are consecutive interior angles.

They are angles on the same side of the transversal but lie within the two straight lines intercepted by the transversal.

✔️<7 and <6 are linear pair angles.

They are angles on a straight line, and sum up to 180°.

3 0
3 years ago
Marking brainliest!<br><br> Please help
Ksju [112]

Answer:

I believe it would be -2

Step-by-step explanation:

The midpoint of (0,4) and (4,-8) is (2,-2)

7 0
3 years ago
Anybody have an answer?
lyudmila [28]

(3+2)^2+(5+4)^2=x^2\\ 5^2+9^2=x^2\\ 25+81=x^2\\ x^2=106\\ x\approx10.3

7 0
3 years ago
The perimeter of a rectangular baking sheet is 58 inches and its area is 201.25 in.2. What are the length and width of the bakin
anzhelika [568]

Answer:

Length=17.5\ in\\\\Width=11.5\ in

Step-by-step explanation:

The formula for calculate the Area of a rectangle is:

A=lw

Where "l" is the lenght and "w" is the width.

And the formula for calculate the peimeter of a rectangle is:

P=2l+2w

Where "l" is the lenght and "w" is the width.

We know that the perimeter of the rectangular baking sheet is 58 inches and its area is 201.25 in². Then:

A=201.25\ in^2\\\\P=58\ in

<u>The steps are:</u>

1. Solve for the "l" from the formula A=lw:

A=lw\\\\l=\frac{A}{w}\\\\\l=\frac{201.25}{w}

2. Substitute l=\frac{201.25}{w} into the formula P=2l+2w and solve for "w":

58=2(\frac{201.25}{w})+2w\\\\58=\frac{402.5}{w}+2w\\\\58=\frac{402.5+2w^2}{w}\\\\58w=402.5+2w^2\\\\2w^2-58w+402.5=0

Applying the Quadratic formula x=\frac{-b\±\sqrt{b^2-4ac}}{2a}, we get:

x=w=\frac{-(-58)\±\sqrt{(-58)^2-4(2)(402.5)}}{2(2)}\\\\w_1=17.5\\\\w_2=11.5

3.  Substitute w_1=17.5 into l=\frac{201.25}{w}:

l=\frac{201.25}{17.5}=11.5

4. Substitute w_2=11.5 into l=\frac{201.25}{w}:

l=\frac{201.25}{11.5}=17.5

Therefore, since the value of the lenght of a rectangle must be greater that the value of the width, we can conclude that the lenght and the width of the rectangular baking sheet are:

l=17.5\ in\\\\w=11.5\ in

8 0
3 years ago
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