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Furkat [3]
3 years ago
12

David wants to make a box plot showing histeam's points for the year. The median score was 7, first quartile was 4, and third qu

artile was 10. The minimum was 2 and the maximum was 20. Explain how David can draw the box plot.

Mathematics
1 answer:
vichka [17]3 years ago
8 0
A dot above 7, 4, 10, 2, and 20. Draw a box around the median, first quartile, and and the third quartile. Then connect the box to the minimum and maximum by drawing a line. Should look like this:

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State the common factor of the terms in the polynomial 5x^2 + 30x^2 - 10x. Then factor the polynomial
tatuchka [14]

Answer:

The common factor is 5x.

The factored polynomial is: 5x(7x - 2)

Step-by-step explanation:

Factor of the numbers:

The common factor of the numbers 5, 30 and 10 is 5, as it is the greater common divisor of them, as found below:

5 - 30 - 10|5

1 - 6 - 2

Factor of the exponents:

Between x^2, x^2 and x, the common factor is the x with the lowest exponent. So x

Common factor

Number multiplied by exponents, so 5x.

Factoring the polynomial:

5x^2 + 30x^2 - 10x = 5x(\frac{5x^2}{5x} + \frac{30x^2}{5x} - \frac{10x}{5x}) = 5x(x + 6x - 2) = 5x(7x - 2)

The factored polynomial is: 5x(7x - 2)

6 0
3 years ago
.
viva [34]
109 with a remainder of 6
Please give brainliest
7 0
3 years ago
Find the third side in simplest radical form:<br> 25
Gre4nikov [31]

Answer:

<h3>\boxed{  \bold{24}}</h3>

Step-by-step explanation:

\mathsf{given}

\mathsf{hypotenuse(h) = 25}

\sf{perpendicular (p) = 7}

\sf{base(b) = }?

Now, Using Pythagoras theorem

\sf{{h}^{2}  =  {p}^{2}  +  {b}^{2} }

plug the values

⇒\sf{  {25}^{2}  =  {7}^{2}  +  {b}^{2} }

Evaluate the power

⇒\sf{625 = 49 +  {b}^{2} }

Swap the sides of the equation

⇒\sf{49 +  {b}^{2}  = 625}

Move constant to right hand side and change it's sign

⇒\sf{ {b}^{2}  = 625 - 49}

Calculate the difference

⇒\sf{ {b}^{2}  = 576}

Squaring on both sides

⇒\sf{b = 24}

Hope I helped!

Best regards!

8 0
3 years ago
What is the justification for each step in solving the inequality?
alekssr [168]
HELLO  ANNA!!

Given inequality
=> −2(x+1)≥3x+8
=>
- 2x - 2 \geqslant 3x + 8 \\ \\ add \: 2 \: in \: both \: sides \\ \\ - 2x \geqslant 3x + 10 \\ \\ subtract \: with \: - 3x \: in \: both \: sides \: \\ \\ - 5x \geqslant 10 \\

now multiply with - on both sides.

As we know now sign will change
=> 5x >_ -10

Now divide by 5 on both sides
=> x >_ -2
HOPE IT HELPED YOU.
4 0
3 years ago
Read 2 more answers
Apply the zero product property to solve the equation below:<br> x (x + 2) = 0
True [87]

Answer:

0(-2+2)=0

Step-by-step explanation:

x=0

x=-2

0(-2+2)=0

3 0
2 years ago
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