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Amiraneli [1.4K]
2 years ago
15

An ocicat eats 3/5 of a pound of food daily. How many ocicats can a 19 1/2-pound bag of food feed for one week?

Mathematics
2 answers:
ipn [44]2 years ago
6 0

Answer:

13 Ocicats

Step-by-step explanation:

Here, we are told that an Ocicat eats 3/5 pounds of food per day.

Now, we have a bag of 19 1/2 pound of food and we want to know the number of Ocicats this will feed

What we just need to do is to divide the weight of the bag by the amount in pounds that can feed a single Ocicat

Thus, we have;

19 1/2 divided by 3/5

= 39/5 divided by 3/5

= 39/5 * 5/3

= 13 Ocicats

kotykmax [81]2 years ago
3 0

Answer:

A 19 1/2 lb of food will feed 4 ocicats for a week and will have 9/14 lb left.

Step-by-step explanation:

The bag contains 19 1/2 lb of food.

One ocicat eats 3/5 lb in 1 day.

To find how many days you can feed 1 ocicat with 19 1/2 lb of food, we divide 19 1/2 lb by 3/5 lb.

19 1/2 ÷ 3/5 = 39/2 × 5/3 = 65/2 = 32.5

The food in 1 bag is enough to feed an ocicat 32.5 days.

A week has 7 days.

32.5/7 = 65/2 × 1/7 = 65/14 = 4 9/14

A 19 1/2 lb of food will feed 4 ocicats for a week and will have 9/14 lb left.

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Find x - and - y intercepts of the following equation. a. 4x - 3y = 12 b. y = 1/3x c. y = 2x + 5 d. y = 6
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✒️ Equation

••••••••••••••••••••••••••••••••••••••

A. To find the x - intercept, let y = 0.

\tt \: \: \large \tt  \: \begin{array}{|c|} \hline \tt \: 4x \:  -  \: 3y \:  =  \: \tt\underline{\green{ 12  }} \\ \tt 4x   \:  -  \: 3(0) \:  =  \: \tt\underline{\blue{ 12  }} \\  \tt4x  \:  -  \: 0 \:  =  \: \tt\underline{\pink{ 12  }} \\  \tt \tt\underline{\red{ \: x \:  =  \: 3  }} \\   \\ \tt \: x  ↬\: the \: intercept\\ \tt\\       \hline\end{array} \:  \\

\\

To find the y - intercept, let x = 0

\large \tt \: \begin{array}{|c|} \hline \tt 4x \:  -  \: 3y \:  =  \: \tt\underline{\green{ 12  }} \\ \tt 4(0) \:  -  \: 3y \:  =  \: \tt\underline{\blue{ 12  }} \\  \tt \: 0 \:  -  \: 3y \:  =  \: \tt\underline{\pink{ 12  }} \\  \tt \tt\underline{\red{ y \:  =  \:  - 4  }} \\ \\     \tt \: x  ↬\: the \: intercept    \\   \ \\ \hline\end{array} \:

\\

B. Replace x with 0 and solve for y. Then replace y with 0 and solve for x.

\large \tt \: \begin{array}{|c|} \hline \tt y \:  -  \: intercept: \: y \:  =  \:  \frac{1}{3}(0) \\   \quad \quad \quad \quad \quad \quad \quad \quad \quad  \tt = \tt\underline{\red{ 0  }} \\  \\ \tt \: x   \: and \:  y ↬ intercepts:  (0,0)\\   \\  \tt \: x \:  ↬ \: intercepts:  \: 0 =  \:  \frac{1}{3} x \\ \quad\quad \quad \quad\quad\quad\quad\quad\quad \:  \tt  \tt\underline{\red{ \: 0 \:  =  \: x  }} \ \\  \\ \hline\end{array} \\

\\

The equation in b is a linear equation in the form y = mx, where m is any real number. the graph of any equation in the form y = mx is always a line that passes through the origin, which means that both the x - and - y - intercepts are (0,0).

\large \tt \: \begin{array}{|c|} \hline \tt intercept \: for \: m \: of \: y \:  =  \: \tt\underline{\red{ mx  }}  \\      \hline\end{array}

\\

C. Replace y with 0, then solve for the x.

\large \tt \: \begin{array}{|c|} \hline \tt x ↬ \: intercept : \: 0 \:  =  \: 2x \:  \ + 5 \\ \\   \tt - 5 \:  =  \: 2x\\ \\  \tt \:  \frac{ - 5}{2}  \:  =  \: x\\   \\  \tt \: x \:  ↬ \: intercept    \ \\ \hline\end{array}

Now, replace x with 0, and then solve for y.

\large \tt \: \begin{array}{|c|} \hline \tt y ↬ \: intercept: \: y \:  =  \: 2(0) \:  +  \: 5 \\ \\ \tt \: y \:  =  \: 0 \:  +  \: 5 \\  \\   \tt \: y \:  =  \: 5 \\  \\   \tt y ↬ \: intercept  \  \\ \\ \hline\end{array}

The equation in 11c is written in the form y = mx + b. note than in the form, when x is replaced by 0 to find the y↬intercept. you are left with the constant b.

\large \tt \: \begin{array}{|c|} \hline \tt \: the \: y  ↬ intercept \: of \: y \:  =  \: mx \:  +  \: b  \\  \hline\end{array}

If the equation is in the form y = mx + b, where m and b are real numbers, then the y ↬intercept is b.

\\

D. Remember that the graph of y = 6 is horizontally line parallel to the x axis that passes through the y axis at (0,6). since the line is parallel to x axis, it will not incest tha x-axis. Hence, there is no x ↬ intercept.

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Answer:

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Step-by-step explanation:

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Antwan determines the distance between the points –7 and 2 on a number line. Maggie determines the difference between the number
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Antawan's solution is the absolute value of Maggie's solution is the solution related to Antawan's and Maggie's solution.

Given

Antawan determines the distance between two points as 9.

Maggie finds the difference between two numbers ₋ 7 ₋ 2 = ₋9

Hence we notice that Antawan's solution is the absolute value to the Maggie's solution.

The non-negative value of x, regardless of its sign, is the absolute value (or modulus) | x | of a real number x. For instance, 5 has an absolute value of 5 and so does 5, which likewise has an absolute value of 5. One way to conceptualize a number's absolute value is as its separation from zero on the real number line.

hence option 2 is right.

Learn more about absolute values here:

brainly.com/question/5012769

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2 years ago
Jane is one of 50 students to take a standardized math test that includes 100 multiple choice questions. If she has the highest
ElenaW [278]

Answer:

Jane is in the 100th percentile.

Step-by-step explanation:

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Komok [63]

Answer:

? ≈ 6.5 yd

Step-by-step explanation:

the area (A) of a triangle is calculated as

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here A = 13.3 and h = 4.1 , then

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