HELP ME IM LOST REALLY IM IN LALA LAND RIGHT NOW

damaskus [11]

Well you didn't finish your sentence

7 0

3 years ago

The data for air traffic in ten days at a busy airport is recorded as follows. Make a stem-and-leaf plot for the given data.

Shalnov [3]

Answer:

Stem and Leaf Plot:

Stem Leaf

28 1 5 7 8

29 3 4 5

30 6 6 9

Minimum: 281

Maximum: 309

Range: 28

Count: 10

Sum: 2944

Mean: 294.4

Median: 293.5

Mode: 306

Standard Deviation: 9.709

Variance: 94.27

6 0

4 years ago

Kaitlyn saves $6 each week. After correctly carrying out the Solve step of the five-step problem-solving plan, which solution sh

ch4aika [34]

Answer:

1. 10 weeks

Step-by-step explanation:

Apparently, we want to find the number of weeks (w) that Kaitlyn must save $6 in order to have a total of $60.

... $6 × w = $60

Divide by $6 to get ...

... w = $60/$6 = 10

Kaitlyn must save for 10 weeks (if she starts with a balance of 0).

_____

Comment on the problem statement

The problem reads like we came in somewhere in the middle of it. We don't know what other steps you've been asked to perform, or any of the details of the problem you're asked to solve. We don't have Kaitllyn's initial balance, for example, which is essential to determining how long she must save. (If Kaitlyn's initial balance is $33, for example, she must only save for 4.5 weeks.)

7 0

3 years ago

If QR= 3x-2, RS= 2x+1, QS=6x-3, and R is between Q and S, then RS=

rewona [7]

Answer:

RS = 5

Step-by-step explanation:

Since R is between Q and S , then

QS = QR + RS , that is

6x - 3 = 3x - 2 + 2x + 1

6x - 3 = 5x - 1 ( subtract 5x from both sides )

x - 3 = - 1 ( add 3 to both sides )

x = 2

Then

RS = 2x + 1 = 2(2) + 1 = 4 + 1 = 5

4 0

3 years ago

Find set A={1, 2, 6, 10} B={3, 6, 9, 10, 11} C = {1, 2, 4, 7, 11}

PilotLPTM [1.2K]

If U = {1, 2, 3, …, 12} is the universal set, and

A = {1, 2, 6, 10}

B = {3, 6, 9, 10, 11}

C = {1, 2, 4, 7, 11}

then

(1) A U B is the set containing all elements from A and B,

A U B = {1, 2, 3, 6, 9, 10, 11}

(2) A ∩ B is the set of elements that are contained in both A and B,

A ∩ B = {6, 10}

(3) Unfortunately, A ∩ B U C is somewhat ambiguous. It could mean (A ∩ B) U C or A ∩ (B U C ). Then either

(A ∩ B) U C = {6, 10} U {1, 2, 4, 7, 11} = {1, 2, 4, 6, 7, 10, 11}

or

A ∩ (B U C ) = {1, 2, 6, 10} ∩ {1, 2, 3, 4, 6, 7, 9, 10, 11} = {1, 2, 6, 10}

The first interpretation is probably the intended one, since that essentially reads the set operations from left to right.

(4) A' U B is the union of A' and B, where A' is the complement of A, or all elements in U that are not in A. We have

A' = U - A = {3, 4, 5, 7, 8, 9, 11, 12}

and so

A' U B = {3, 4, 5, 6, 7, 8, 9, 10, 11, 12}

(5) We have

A U C = {1, 2, 4, 6, 7, 10, 11}

so that

(A U C )' = U - (A U C ) = {3, 5, 8, 9, 12}

(6) We have

B' = U - B = {1, 2, 4, 5, 7, 8, 12}

and so

A ∩ B' = {1, 2}

(7) Using the complements found in (4) and (6), we have

A' U B' = {1, 2, 3, 4, 5, 7, 8, 9, 11, 12}

Alternatively, we can use the fact that

A' U B' = (A ∩ B)'

and since we know from (2) that A ∩ B = {6, 10}, we end up with the same result,

(A ∩ B)' = U - (A ∩ B) = {1, 2, 3, 4, 5, 7, 8, 9, 11, 12}

(8) We have

A U B U C = {1, 2, 3, 4, 6, 7, 9, 10, 11}

so that

(A U B U C )' = {5, 8, 12}

6 0

3 years ago