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sp2606 [1]
3 years ago
5

4. Bryce has 220 feet of fencing that will enclose a rectangular corral. One side of the corral will be 48 ft long. What will be

the area of the corral?
Mathematics
2 answers:
RideAnS [48]3 years ago
7 0

Answer:

The area of the rectangular coral = 2,976 ft²

Step-by-step explanation:

Bryce has 220 ft of fencing to fence a rectangular coral.

Let the dimensions of the corral be x ft. × y ft.

One side of the coral is 48 ft. long

A rectangle has 4 sides, with each of the two opposite sides with the same dimension. Hence, the perimeter of the rectangular coral = 2(x + y) = 2x + 2y.

Total length of material for fencing = 220 ft.

Hence the perimeter of the reef = 220 ft.

2x + 2y = 220

And one length of the rectangular coral = x = 48 ft.

We can solve for the remaining dimension of the rectangular coral this way.

2(48) + 2y = 220

2y = 220 - 96 = 124

y = (124/2) = 62 ft.

Hence, the area of the rectangular coral = xy = 48 × 62 = 2,976 ft²

Hope this Helps!!!

allochka39001 [22]3 years ago
6 0

Answer:

2,976 ft2

Step-by-step explanation:

The perimeter of the corral needs to be 220 feet, so:

2*length + 2*width = 220 feet

length + width = 110 feet

If one side of the corral will be 48 feet (let's say the width), we have that:

length + 48 = 110

length = 110 - 48 = 62 feet

So the area of the corral is:

Area = length * width = 62 * 48 = 2,976 ft2

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Read 2 more answers
Can someone pls help??
Vlad1618 [11]

Answer:

a. The y coordinates for A are either 10 or -14

b.  The y coordinates for A are either -11 or 7

Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

15 = sqrt ((-9)^2+(-2-y1)^2)

15 = sqrt (81+(-2-y1)^2)

Square each side

15^2 =sqrt (81+(-2-y1)^2)^2

225 =  81+(-2-y1)^2

Subtract 81 from each side

225-81 = 81-81 +(-2-y1)^2

144 = (-2-y1)^2

Take the square root of each side

±sqrt 144 = sqrt(-2-y1)^2

±12 = (-2-y1)

Add 2 to each side

2±12 = 2-2-y1

2±12 = -y1

14 = -y1  or -10 = -y1

Multiply by -1

-14 = y1  or 10 = y1

The y coordinates for A are either 10 or -14

Now move B to -7,-2

15 = sqrt ((-7-5)^2+(-2-y1)^2)

15 = sqrt ((-12)^2+(-2-y1)^2)

15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

225 =  144+(-2-y1)^2

Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

81 = (-2-y1)^2

Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

2±9 = -y1

11 = -y1  or -7 = -y1

Multiply by -1

-11 = y1  or 7 = y1

The y coordinates for A are either -11 or 7

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