1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
guapka [62]
2 years ago
10

In a certain population of the eastern thwump bird, the wingspan of the individual birds follows an approximately normal distrib

ution with mean 53.0 mm and standard deviation 6.25 mm. A sample of five birds is drawn from the population. [Note: give your answers up to 4 decimal places.](a) Find the probability that the wingspan of the first bird chosen is between 48 and 58 mm long.(b) Find the probability that at least one of the five birds has a wingspan between 48 and 58 mm.In addition,(c) What is the expected number of birds in this sample whose wingspan is between 48 and 58 mm.(d) Find the probability that the wingspan of a randomly chosen bird is less than 48 mm long.(e) Find the probability that more than two of the five birds have wingspans less than 48 mmlong.
Mathematics
1 answer:
Greeley [361]2 years ago
5 0

Answer:

a) P(48 < x < 58) = 0.576

b) P(X ≥ 1) = 0.9863

c) E(X) 2.88

d) P(x < 48) = 0.212

e) P(X > 2) = 0.06755

Step-by-step explanation:

The mean of the wingspan of the birds = μ = 53.0 mm

The standard deviation = σ = 6.25 mm

a) Probability of a bird having a wingspan between 48 mm and 58 mm can be found by modelling the problem as a normal distribution problem.

To solve this, we first normalize/standardize the two wingspans concerned.

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ

For wingspan 48 mm

z = (48 - 53)/6.25 = - 0.80

For wingspan 58 mm

z = (58 - 53)/6.25 = 0.80

To determine the probability that the wingspan of the first bird chosen is between 48 and 58 mm long. P(48 < x < 58) = P(-0.80 < z < 0.80)

We'll use data from the normal probability table for these probabilities

P(48 < x < 58) = P(-0.80 < z < 0.80) = P(z < 0.8) - P(z < -0.8) = 0.788 - 0.212 = 0.576

b) The probability that at least one of the five birds has a wingspan between 48 and 58 mm = 1 - (Probability that none of the five birds has a wingspan between 48 and 58 mm)

P(X ≥ 1) = 1 - P(X=0)

Probability that none of the five birds have a wingspan between 48 and 58 mm is a binomial distribution problem.

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = number of birds = 5

x = Number of successes required = number of birds with wingspan between 48 mm and 58 mm = 0

p = probability of success = Probability of one bird having wingspan between 48 mm and 58 mm = 0.576

q = probability of failure = Probability of one bird not having wingspan between 48 mm and 58 mm = 1 - 0.576 = 0.424

P(X=0) = ⁵C₀ (0.576)⁰ (1 - 0.576)⁵ = (1) (1) (0.424)⁵ = 0.0137

The probability that at least one of the five birds has a wingspan between 48 and 58 mm = P(X≥1) = 1 - P(X=0) = 1 - 0.0137 = 0.9863

c) The expected number of birds in this sample whose wingspan is between 48 and 58 mm.

Expected value is a sum of each variable and its probability,

E(X) = mean = np = 5×0.576 = 2.88

d) The probability that the wingspan of a randomly chosen bird is less than 48 mm long

Using the normal distribution tables again

P(x < 48) = P(z < -0.8) = 1 - P(z ≥ -0.8) = 1 - P(z ≤ 0.8) = 1 - 0.788 = 0.212

e) The probability that more than two of the five birds have wingspans less than 48 mm long = P(X > 2) = P(X=3) + P(X=4) + P(X=5)

This is also a binomial distribution problem,

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = number of birds = 5

x = Number of successes required = number of birds with wingspan less than 48 mm = more than 2 i.e. 3,4 and 5.

p = probability of success = Probability of one bird having wingspan less than 48 mm = 0.212

q = probability of failure = Probability of one bird not having wingspan less than 48 mm = 1 - p = 0.788

P(X > 2) = P(X=3) + P(X=4) + P(X=5)

P(X > 2) = 0.05916433913 + 0.00795865476 + 0.00042823218

P(X > 2) = 0.06755122607 = 0.06755

You might be interested in
Suppose that a visitor to Disneyland has a 0.74 probability of riding the Jungle Cruise, 0.62 probability of riding the Monorail
erastova [34]

Answer: 0.98

Step-by-step explanation:

Let J denotes Jungle Cruise , M denotes Monorail and H denotes Matterhorn.

As per given ,

P(J) = 0.74,  P(M) =  0.62, P(H) = 0.70

P(J∩M) = 0.52,  P(J∩H)= 0.46 , P(M∩H)=0.44

P(J∩M∩H)=0.34

Now , the required probability:

P(J∪M∪H) = P(J) + P(M)  + P(H) - P(J∩M) - P(J∩H) - P(M∩H)+ P(J∩M∩H)

= 0.74+0.62+0.70-0.52-0.46-0.44+0.34

= 0.98

Hence, the probability that a person visiting Disneyland will go on at least one of these three rides= 0.98 .

6 0
2 years ago
You don't have to do all of them
vova2212 [387]

Answer: lol your using canvas

1. 63

2. D

3. B

4. A

Sorry for the bland explinations havin a bad day.

Step-by-step explanation:

1. The way we solve this is by adding the degrees 72 and 45. then we subtract it by 180. this is because in all triangles the angles always add up to 180 degrees.

2. Like question one what set of angles measures to 180 degrees.

3. The sides of a triangle should define the angle measurements. you can also see if its a triangle if the numbers are continues like 3,4,5 or in this case 4,5,6

4. like in questions 1 and 2 the angles of a triangle has to equal 180 degrees so 60 times 3 is 180 so each angle would have to be 60 degrees.

7 0
2 years ago
Help..idk how to do algabra. i didn't pay attention..
kotegsom [21]
Start with 3 one-by-one squares. This represents the '3' in 4t+3

Then draw 4 rectangles that are vertical or horizontal. Make sure the rectangle is longer than it is wide, or vice versa. The longer side is t units long (t is just a placeholder for a number). The shorter side is 1 unit long

The longer thin rectangles have an area of 1*t = t square units. Four of them represent t+t+t+t = 4*t = 4t
The small squares have an area of 1*1 = 1. Three of them represent 1+1+1 = 1*3 = 3

This is one possible way to draw it out. See the attached drawing. 

4 0
3 years ago
What is the answer?How do you solve this?
Alika [10]

Answer:

you have to look at the chart and use the chart to answer the questions at the botttom

Step-by-step explanation:

4 0
3 years ago
The Dewey Civic Center has 1,600 seats. Tickets for 85% of the total number of seats were sold. How many tickets were sold?
Juliette [100K]
1600×85%=1360 I think that 1360 Tickets were sold
4 0
3 years ago
Other questions:
  • I need help on all of these plz
    10·1 answer
  • A jug of orange juice can fill 4 large mugs. A large mug can fill 5 small cups. How many jugs of orange juice are needed to fill
    7·2 answers
  • How to make a math question out of 14-7
    13·1 answer
  • Explain why multiplying 37.4×0.7 gives a product that is less than 37.4
    14·2 answers
  • Help will mark brainiest
    12·1 answer
  • Help me on this question please!
    9·1 answer
  • A circle has a center at A (-3,4) and radius of 4 units. What is the equation of the circle? Show work!
    5·1 answer
  • Helpppppppppppppppppppppp
    10·2 answers
  • If ram have 30 apple&amp; each apple rs is 26 . 14 are rotten .he had eat 9 apple. 6 apple he sold each price 35 . Now say me ra
    15·1 answer
  • Can someone please help me
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!