From one vertex of an octagon you can draw 5 diagonals.
There are 8 vertices in an octagon, and we are choosing one as our starting vertex. There are then 7 vertices left to draw a line to, but 2 of the vertices are already connected to our main vertex (because they are connected along the side of the octagon). That leaves 5 vertices to draw a diagonal to from our original vertex.
Step-by-step explanation:
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Answer:
-9.85
Step-by-step explanation:
-15.5 - 4.2 = -19.7
Negatives work like positives
19.7 / 2 = 9.85
Turn that into a negative
-9.85
Answer:
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<span>Using: a^2 + b^2 = c^2 (pythagoras theorem)
where 'a' and 'b' are the legs of a right triangle, c is the hypotenuse
</span><span>compare the triangle I just drew to the triangle you have for your problem
</span><span>you'll see that a = unknown b = 18 c = 36
</span><span>a=18sqrt3
=31.2</span>