27 (circumference) ➗ 3.14 (pi) = 8.59 (diameter)
Distance across (diameter) would be closest to 9.
Answer:
<em>The first step is to determine the average
</em>

<em>The exercise says it’s a normal distribution: (n=8)</em>

<em>According to the exercise, the mean is equal to 0,5 then the value of t of the distribution can be obtained
</em>
<em />

<em>The variable t has 7 grade to liberty, we calculate the p-value as:
</em>

This value is very high, therefore the hypothesis is not rejected
Answer:
f(2) = 2.5×2-10.5
=5-10.5
=-5.5
g(2) = 64(0.5×2)
= 64×1
=64
f(3)=2.5×3-10.5
=7.5-10.5
=-3
g(3)=64(0.5×3)
=64×1.5
=96
f(4)=2.5×4-10.5
=10-10.5
=-500
g(4)=64(0.5×4)
=64×2
=128
f(5)=2.5×5-10.5
=12.5-10.5
=2
g(5)=64(0.5×5)
=64×2.5
=150
I think it is the processs It will help you
Answer: I think its the last one
Step-by-step explanation:
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