Given Information:
Population mean = p = 60% = 0.60
Population size = N = 7400
Sample size = n = 50
Required Information:
Sample mean = μ = ?
standard deviation = σ = ?
Answer:
Sample mean = μ = 0.60
standard deviation = σ = 0.069
Step-by-step explanation:
We know from the central limit theorem, the sampling distribution is approximately normal as long as the expected number of successes and failures are equal or greater than 10
np ≥ 10
50*0.60 ≥ 10
30 ≥ 10 (satisfied)
n(1 - p) ≥ 10
50(1 - 0.60) ≥ 10
50(0.40) ≥ 10
20 ≥ 10 (satisfied)
The mean of the sampling distribution will be same as population mean that is
Sample mean = p = μ = 0.60
The standard deviation for this sampling distribution is given by

Where p is the population mean that is proportion of female students and n is the sample size.

Therefore, the standard deviation of the sampling distribution is 0.069.
Answer:
The height of the equilateral triangle is 24 units
Step-by-step explanation:
In the question above, the unit of the side of the equilateral triangle is not given. If the complete question is:
Triangle MNO is an equilateral triangle with sides measuring 16 square root of 3 units, then the length of each side is 16√3 units.
To find the height of the triangle, we use Pythagoras theorem
MP^2 + PO^2 = MO^2
Let MP^2 be x
x^2 + {(16√3)/2}^2 = (16√3)^2
X^2 + (256*3)/4 = 256*3
4x^2 + 768 = 768* 4
4x^2 + 768 = 3072
4x^2 = 3072-768
4x^2 = 2304
X^2 = 2304/4
X^2 = 576
x= √576
x = 24 units
Answer:
99
Step-by-step explanation:
12x4=48
12x3=36
12-4-5=3
3x5=15
48+36+15=99
A. from 67.86 all the way to the end. (67.86 is not filled)
b. $67.86,
$80.00,
$70.00(values equal to or greater than $67.86.)
c. There are many values that represent this inequality.(values equal to or greater than $67.86)
Hope this helped☺☺