Answer:
Step-by-step explanation:
This is a differential equation problem most easily solved with an exponential decay equation of the form
. We know that the initial amount of salt in the tank is 28 pounds, so
C = 28. Now we just need to find k.
The concentration of salt changes as the pure water flows in and the salt water flows out. So the change in concentration, where y is the concentration of salt in the tank, is . Thus, the change in the concentration of salt is found in
inflow of salt - outflow of salt
Pure water, what is flowing into the tank, has no salt in it at all; and since we don't know how much salt is leaving (our unknown, basically), the outflow at 3 gal/min is 3 times the amount of salt leaving out of the 400 gallons of salt water at time t:
Therefore,
or just
and in terms of time,
Thus, our equation is
and filling in 16 for the number of minutes in t:
y = 24.834 pounds of salt
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Multiply both sides by d.
dm=a+64d
Flip the equation.
a+64d=dm
Add -64d to both sides.
a=dm−64d
Answer:
<u>a=dm−64d</u>
Answer:
x = 11
Step-by-step explanation:
The angle formed by two secants is half the difference of the intercepted arc angles.
m∠D = ½ (mBS − mCE)
60 = ½ (173 − (5x − 2))
120 = 173 − 5x + 2
5x = 55
x = 11
C = 4
Use the formula a^2 + b^2 = c^2
5 = a and 4 = b