Answer:
Step-by-step explanation:
You only need to isolate the term a to solve this problem.
Add by 3 from both sides.
Solve.
0+3=3
a/7<3
Multiply by 7 from both sides.
Solve.
3*7=21
<u>a<21</u>
As a result, the solution is a<21, which is our answer.
Group and factor
undistribute then undistribute again
remember
ab+ac=a(b+c)
this is important
6d^4+4d^3-6d^2-4d
undistribute 2d
2d(3d^3+2d^2-3d-2)
group insides
2d[(3d^3+2d^2)+(-3d-2)]
undistribute
2d[(d^2)(3d+2)+(-1)(3d+2)]
undistribute the (3d+2) part
(2d)(d^2-1)(3d+2)
factor that difference of 2 perfect squares
(2d)(d-1)(d+1)(3d+2)
77.
group
(45z^3+20z^2)+(9z+4)
factor
(5z^2)(9z+4)+(1)(9z+4)
undistribuet (9z+4)
(5z^2+1)(9z+4)
Answer:
I believe the answer is D?
Step-by-step explanation:
Answer:
256 train or 80% of the trains arrived on time
Step-by-step explanation:
Total trains that arrived in a week = 320 trains
Late = 5% of 320
early = 15% of 320
On time = 320 - (15 + 5% of 320)
=> 320 - (20% * 320)
=> 320 - 64
=> 256
Therefore, 256 train or 80% of the trains arrived on time
Hope my answer helps :)
Answer:
182
Step-by-step explanation:
x-y =30
first we need to replace y woth the value given in the question.
x - 152 = 30
x = 30 + 152
x = 182
