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Goshia [24]
3 years ago
9

HELP I WILL GIVE 5 POINTS TO WHOM EVER CAN ANSWER THESE LAST 2 QUESTIONS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
75.
6d^4 + 4d^3 - 6d^2 - 4d

77.
45z^3 + 20z^2 + 9z + 4
Mathematics
1 answer:
vodka [1.7K]3 years ago
7 0
Group and factor
undistribute then undistribute again
remember
ab+ac=a(b+c)
this is important



6d^4+4d^3-6d^2-4d
undistribute 2d
2d(3d^3+2d^2-3d-2)
group insides
2d[(3d^3+2d^2)+(-3d-2)]
undistribute
2d[(d^2)(3d+2)+(-1)(3d+2)]
undistribute the (3d+2) part
(2d)(d^2-1)(3d+2)
factor that difference of  2 perfect squares
(2d)(d-1)(d+1)(3d+2)






77.
group
(45z^3+20z^2)+(9z+4)
factor
(5z^2)(9z+4)+(1)(9z+4)
undistribuet (9z+4)
(5z^2+1)(9z+4)
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In class 9A the ratio of boys to girls is 3:4. if there are 12 boys,how many girls are there?​
Mamont248 [21]

16 girls. 12 divided by 4 is 3, so this means that you have to take 4 and multiply it by 4 which equals to 16.

3 0
2 years ago
Simplify -3+6i-(-5-3i)-8i​
borishaifa [10]

Answer:

2 +i

Step-by-step explanation:

-3+6i-(-5-3i)-8i​

Distribute the minus sign

-3 +6i +5 +3i -8i

Combine like terms

-3+5 +6i +3i -8i

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4 0
3 years ago
Is the equation true, false, or open? Explain. -9a + 3 = -9a + 3* 5
Sholpan [36]

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8 0
2 years ago
48/64 Which choices are equivalent to the fraction below? Check all that apply. A. 8/6 B. 3/4 C. 6/8 D. 12/16 E. 9/12 F. 24/32​
irinina [24]

Answer:

B, C, D, F

Step-by-step explanation:

to simplify the fraction 48/64, you need to divide both the numerator and denominator by their common factors. B is correct since you can divide both by 16, C is correct since both are divisible by 8, D is correct since both are divisible by 4, and F is correct since both are divisible by 2. A, however, would be correct only if the fraction were 64/48 and E would only be correct if 9 was a factor of 48 and 12 was a factor of 64, however neither haev such factors.  

5 0
3 years ago
Read 2 more answers
Find the common ratio for the geometric sequence defined by the formula: an=40(2‾√)n−1 a n = 40 ( 2 ) n − 1
WITCHER [35]

The ratio of the geometric sequence 402^{n-1} is 2.

Given that geometric sequence is 40*2^{n-1} and we have to find the common ratio of all the terms.

Geometric sequence is a sequence in which all the terms have a common ratio.

Nth termof a GP is ar^{n-1} in which a is first term and r is common ratio.

Geometric sequence=40*2^{n-1}

We have to first find the first term, second term and third term of a geometric progression.

First term=40*2^{1-1}

=40*2^{0}

=40*1

=40

Second term=40*2^{2-1}

=40*2^{1}

=40*2

=80

Third term=40*2^{3-1}

=40*2^{2}

=40*4

=160

Ratio of first two terms=80/40=2

Ratio of next two terms=160/80=2

Hence the common ratio of geometric sequence is 2.

Learn more about geometric progression at brainly.com/question/12006112

#SPJ1

4 0
2 years ago
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