Question

Software that can be used to detect fraund in customer

Answer 1

Answer:

0.002991

Step-by-step explanation:

Let

User is legitimate one = E₁

User is fraudulent one = E₂

User originates calls from two metropolitan = A

Therefore, according to the question

P(E₁) = 1 - 0.01% = 1 - 0.0001 = 0.9999

P(E₂) = 0.0001

P(A/E₁) = 1% = 0.01

P(A/E₂) = 30% = 0.30

Now,

P(E₂/A) = $\frac{P(E_2)\timesP(A/E_1)}{P(E_1)\timesP(A/E_1)+P(E_2)\timesP(A/E_2)}$

or

P(E₂/A) = $\frac{0.9999\times0.01}{0.0001\times0.01+0.0001\times0.3}$

or

P(E₂/A) = 0.002991