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Sonja [21]
3 years ago
11

What is 5x+2y=-49 if -9<= x <=-7?

Mathematics
1 answer:
Arlecino [84]3 years ago
5 0
I’m not quite sure I understand but if your saying that -9 =x and -7 =y then the answer would be -59 so the equation wouldn’t be true I hoped I helped :)
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Why will percent of change always be represented by a positive number?
Murljashka [212]
Percent of change will always be positive because the change is an absolute value. As we know, absolute value is always a positive value because you don't pay attention to the direction, only the distance is important. 
3 0
3 years ago
Help!!!!!! I’ll give 100 points
Mama L [17]

Answer:

your answer is c :)

7 0
2 years ago
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PLEASE HELP I AM STUCK!!!THESE ARE ALL MY POINTS!!!
Bond [772]

Answer:

come back when you have the number for the 32oz

Step-by-step explanation:

8 0
3 years ago
Bethany, Lauren, Amanda, and David all meet at a family reunion. They are comparing their ages. They have found that Lauren is 1
tekilochka [14]
Lauren =l
David=d
Bethany's =x
Amanda =y
l=x+13
d=y+11
lx=2y
<span>(x+13)x=2y
</span>2y=x^2+13x
y= \frac{1}{2}(x^2+13x)
or
y= \frac{x^2}{2}+ \frac{13}{2}x
(x-20)(l-20)=d
<span>(x-20)(x+13-20)=y+11 </span><span>
</span>y+11=(x-20)(x-7)
y+11=x^2-27x+140
y=x^2-27x+129
so I believe its b
Hope this helps :)
6 0
3 years ago
Read 2 more answers
The mean annual cost of an automotive insurance policy is normally distributed with a mean of $1140 and standard deviation of $3
DerKrebs [107]

Using the normal distribution, it is found that the probabilities are given as follows:

a) 0.8871 = 88.71%.

b) 0.0778 = 7.78%.

c) 0.8485 = 84.85%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

The parameters in this problem are given as follows:

\mu = 1140, \sigma = 310, n = 16, s = \frac{310}{\sqrt{16}} = 77.5

Item a:

The probability is the <u>p-value of Z when X = 1250 subtracted by the p-value of Z when X = 1000</u>, hence:

X = 1250:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1250 - 1140}{77.5}

Z = 1.42

Z = 1.42 has a p-value of 0.9222.

X = 1000:

Z = \frac{X - \mu}{s}

Z = \frac{1000 - 1140}{77.5}

Z = -1.81

Z = -1.81 has a p-value of 0.0351.

0.9222 - 0.0351 = 0.8871 = 88.71% probability.

Item b:

The probability is <u>one subtracted by the p-value of Z when X = 1250</u>, hence:

1 - 0.9222 = 0.0778 = 7.78%.

Item c:

The probability is the <u>p-value of Z when X = 1220</u>, hence:

Z = \frac{X - \mu}{s}

Z = \frac{1220 - 1140}{77.5}

Z = 1.03

Z = 1.03 has a p-value of 0.8485.

0.8485 = 84.85% probability.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0
2 years ago
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