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3 years ago

What fraction is greater than C on the given number line above?

Mathematics

2 answers:

nydimaria [60]3 years ago

6 0

Answer:

2 is greater than C on the number line

Step-by-step explanation:

Ghella [55]3 years ago

4 0

Answer:

2/5

Step-by-step explanation:

C is at the second tick of 6 segements, so C = 2/6 = 1/3.

If we convert all fractions to /60, you can easily see the answer:

1/3 = 20/60

2/5 = 24/60

1/4 = 15/60

1/5 = 12/60

So we're looking for an answer larger than 20/60, which is only 24/60, a.k.a. 2/5.

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The volume of a right circular cone is 2,279.64 in cubed. If the height of the cone is 18 in, what is the diameter of the cone?

Aleksandr [31]

ANSWER

A. 22 in

EXPLANATION

The volume of a cone is calculated using the formula:

$Volume = \frac{1}{3} \times \pi {r}^{2} h$

It was given that: the volume is 2,279.64 in³

The height of the cylinder is also given as: h=18 in.

We substitute, the given values into the formula to get:

$2279.64= \frac{1}{3} \times (3.14) \times {r}^{2} \times 18$

$2279.64= 18.84 {r}^{2}$

${r}^{2} = \frac{2279.64}{18.84}$

${r}^{2} = 121$

We take positive square root to get;

$r = \sqrt{121}$

$r = 11in$

Therefore the diameter is 2(11) which is equal to 22 inches.

5 0

3 years ago

On Monday, the temperature at 10 a.m. at Sam’s house was –6° Fahrenheit. The

Alika [10]

Answer:

Step-by-step explanation:

to find the answer, subtract the second amount (2) from the first amount (-6), -6 - 2 = -8, the temperat decreased by 8

6 0

2 years ago

Read 2 more answers

Solve the equation on the interval [0,2π]

WARRIOR [948]

$\bf 16sin^5(x)+2sin(x)=12sin^3(x)
\\\\\\
16sin^5(x)+2sin(x)-12sin^3(x)=0
\\\\\\
\stackrel{common~factor}{2sin(x)}[8sin^4(x)+1-6sin^2(x)]=0\\\\
-------------------------------\\\\
2sin(x)=0\implies sin(x)=0\implies \measuredangle x=sin^{-1}(0)\implies \measuredangle x=
\begin{cases}
0\\
\pi \\
2\pi 
\end{cases}\\\\
-------------------------------$

$\bf 8sin^4(x)+1-6sin^2(x)=0\implies 8sin^4(x)-6sin^2(x)+1=0$

now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,

$\bf 8sin^4(x)-6sin^2(x)+1=0\implies 8[~[sin(x)]^2~]^2-6[sin(x)]^2+1=0
\\\\\\
~~~~~~~~~~~~\textit{quadratic formula}
\\\\
\begin{array}{lcccl}
& 8 sin^4& -6 sin^2(x)& +1\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array} 
\qquad \qquad 
sin(x)= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}
\\\\\\
sin(x)=\cfrac{-(-6)\pm\sqrt{(-6)^2-4(8)(1)}}{2(8)}\implies sin(x)=\cfrac{6\pm\sqrt{4}}{16}
\\\\\\
sin(x)=\cfrac{6\pm 2}{16}\implies sin(x)=
\begin{cases}
\frac{1}{2}\\\\
\frac{1}{4}
\end{cases}$

$\bf \measuredangle x=
\begin{cases}
sin^{-1}\left( \frac{1}{2} \right)
sin^{-1}\left( \frac{1}{4} \right)
\end{cases}\implies \measuredangle x=
\begin{cases}
\frac{\pi }{6}~,~\frac{5\pi }{6}\\
----------\\
\approx~0.252680~radians\\
\qquad or\\
\approx~14.47751~de grees\\
----------\\
\pi -0.252680\\
\approx 2.88891~radians\\
\qquad or\\
180-14.47751\\
\approx 165.52249~de grees
\end{cases}$

3 0

3 years ago

Which of the following<br> is equivalent to 4/5 ?<br> Select your answers) below

kondor19780726 [428]

We need the options to help

3 0

2 years ago

Plz HELP! ASAP for both 9 and 10 plz

ale4655 [162]

Answer:

domain: 0 - 10 range: 0 - 32

Step-by-step explanation:

Take the lowest x and the highest x and put them in set values to get domain.

lowest x = 0 and highest x = 10.

Take the lowest y and the highest y and put them in set values to get range.

lowest y = 0 and highest y = 32

8 0

3 years ago

Read 2 more answers