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3 years ago

PLEASE HELP ME ASAP!!!!!!!!!

Mathematics

1 answer:

Marina86 [1]3 years ago

3 0

Answer: B) 2&3

Step-by-step explanation:

7/3 is 2.33333 repeating which in a complete fraction is 2 1/3.

On a number line, your answer would between 2 and 3.

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Based on the diagram select all that apply.

Sveta_85 [38]

Answer:

Step-by-step explanation:

I just think so. Maybe it's right

4 0

3 years ago

Question Help Suppose that the lifetimes of light bulbs are approximately normally distributed, with a mean of 5656 hours and a

koban [17]

Answer:

a)3.438% of the light bulbs will last more than 6262 hours.

b)11.31% of the light bulbs will last 5252 hours or less.

c) 23.655% of the light bulbs are going to last between 5858 and 6262 hours.

d) 0.12% of the light bulbs will last 4646 hours or less.

Step-by-step explanation:

Normally distributed problems can be solved by the z-score formula:

On a normaly distributed set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a value X is given by:

$Z = \frac{X - \mu}{\sigma}$

After we find the value of Z, we look into the z-score table and find the equivalent p-value of this score. This is the probability that a score will be LOWER than the value of X.

In this problem, we have that:

The lifetimes of light bulbs are approximately normally distributed, with a mean of 5656 hours and a standard deviation of 333.3 hours.

So $\mu = 5656, \sigma = 333.3$

(a) What proportion of light bulbs will last more than 6262 hours?

The pvalue of the z-score of $X = 6262$ is the proportion of light bulbs that will last less than 6262. Subtracting 100% by this value, we find the proportion of light bulbs that will last more than 6262 hours.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6262 - 5656}{333.3}$

$Z = 1.82$

$Z = 1.81$ has a pvalue of .96562. This means that 96.562% of the light bulbs are going to last less than 6262 hours. So

$P = 100% - 96.562% = 3.438%$ of the light bulbs will last more than 6262 hours.

(b) What proportion of light bulbs will last 5252 hours or less?

This is the pvalue of the zscore of $X = 5252$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5252- 5656}{333.3}$

$Z = -1.21$

$Z = -1.21$ has a pvalue of .1131. This means that 11.31% of the light bulbs will last 5252 hours or less.

(c) What proportion of light bulbs will last between 5858 and 6262 hours?

This is the pvalue of the zscore of $X = 6262$ subtracted by the pvalue of the zscore $X = 5858$

For $X = 6262$ , we have that $Z = 1.81$ with a pvalue of .96562.

For X = 5858

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5858- 5656}{333.3}$

$Z = 0.61$

$Z = 0.61$ has a pvalue of .72907.

So, the proportion of light bulbs that will last between 5858 and 6262 hours is

$P = .96562 - .72907 = .23655$

23.655% of the light bulbs are going to last between 5858 and 6262 hours.

(d) What is the probability that a randomly selected light bulb lasts less than 4646 hours?

This is the pvalue of the zscore of $X = 4646$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4646- 5656}{333.3}$

$Z = -3.03$

$Z = -3.03$ has a pvalue of .0012. This means that 0.12% of the light bulbs will last 4646 hours or less.

5 0

3 years ago

A tropical punch recipe calls for 300 ml of sugar for every 222 flavor packages. Write an equation that shows the relationship b

mihalych1998 [28]

Answer:

s = 150f

Step-by-step explanation:

A tropical punch recipe calls for 300 ml of sugar for every 2 flavor packages. Write an equation that shows the relationship between s, the amount of sugar in milliliters, and f, the number of flavor packages for this recipe.

The amount of sugar in milliliters = s

The amount of flavor packages for these recipe = f

The relationship between 2 variables

= y ∝ x

y = kx

k = constant of proportionality

Hence:

s ∝ f

s = kf

Note ,

s = 300

f = 2

300 = 2k

k = 300/2

k = 150

Therefore, the equation that shows the relationship between s, the amount of sugar in milliliters, and f, the number of flavor packages for this recipe is:

s = kf

s = 150f

3 0

3 years ago

Neeed helps math help no links or imma report helps 20 points

Ivan

The answer to the question u asked is A

8 0

3 years ago

A farmer plowed a rectangular section of land for a new crop. The section measures 24 1/2 yd by 38 1/2 yd. Find the total area i

MAVERICK [17]

Answer: $943\dfrac{1}{4}\text{ sq. yds}$

Step-by-step explanation:

Given , A farmer plowed a rectangular section of land for a new crop.

Dimensions of the section is given by :-

Length by width = $24\dfrac{1}{2}\text{ yd by }38\dfrac{1}{2}\text{ yd}$

Since , the area of a rectangle = length x width

Then, the total area in yards of plowed section of land will be:

$24\dfrac{1}{2}\times38\dfrac{1}{2}\text{ sq. yds}\\\\=\dfrac{2(24)+1}{2}\times\dfrac{2(38)+1}{2}\text{ sq. yds}\\\\=\dfrac{49}{2}\times\dfrac{77}{2}\text{ sq. yds}\\\\=\dfrac{3773}{4}\text{ sq. yds}\\\\=943\dfrac{1}{4}\text{ sq. yds}$

Hence, the total area in yards of plowed section of land = $943\dfrac{1}{4}\text{ sq. yds}$

8 0

3 years ago