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3 years ago

Help help me please

Mathematics

2 answers:

prisoha [69]3 years ago

7 0

Answer:

1. -15,-10,-5,0,5,10,15,20,25,30

Step-by-step explanation:

For number one, you are incresing by 5 each time -15+5= -10, -10+5=-5, and so on

For each problem you are incresing or decreasing by a specific value, just subtract from the last number to find the value :)

galben [10]3 years ago

3 0

I only do the blanks

1) ... 0, 5, 15, 15, 20, 25, 30

2) 0, 3, 6, ... 15, 18, 21, ... 25

3) 96, 100, ... 108, ... 116, 120, 124, 128

4) -109, ... -97, -91, ... -73, -67, -61, -55

5) 893, ... 899, 902, ... 911, 914, 917, 920

BRUH Just do it from there

You made my brain die

just figure out from one number to the next

And use it

Im sorry but not sorry

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Given that MN = 5, NO = 12, and MO = 13, find cos O.

Galina-37 [17]

Answer:

12/13

Step-by-step explanation:

Given that MN = 5, NO = 12, and MO = 13, find cos O.

Since the reference angle is P, hence;

MN is the opposite = 5

MO is the hypotenuse = 13 (longest side)

NO is the adjacent = 12

Cos O = adj/hyp

Substitute the given values

Cos O = 12/13

Hence the value of Cos O is 12/13

8 0

3 years ago

Margaret is saving money for her summer vacation. She calculates that her starting amount is 0.4% of the total amount she wants

garri49 [273]

0.4% can be written as 0.004 in decimal.

Step-by-step explanation:

Let the total amount she wants to save be 'a'

Starting amount = 0.4% of the total amount

= 0.4% of a

= (0.4/100) a

0.4% = 0.4/100

= 0.004

0.4% can be written as 0.004 in decimal.

5 0

3 years ago

HELP ASAP <br> What is the slope of the line on the graph?

ollegr [7]

The slope of this line is -1/6.

2 Point: (6,2) (-6,6)
x₁ y₁ x₂ y₂

Remember:

rise change in y y₂ - y₁ 6 - 2 4
---------- = ------------------- = ------------- = ----------- = ----------
run change in x x₂ - x₁ -6 - 6 -12

Simplify 4/-12

4 ÷ 4 1
------- = ------------- = -1/3
-12 ÷ 4 -3

The slope of the line is -1/3.

3 0

3 years ago

ABCD is a trapezoid.<br> What is the area of trapezoid?

lana [24]

Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h

The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²

The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h

Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²

Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²

6 0

3 years ago

Which expression represents it??

torisob [31]

Answer:

The third answer that is C is correct

7 0

3 years ago