Since all three equations are equal, you take 15 x 20, which =300, once again because all of the equations are equal, take 300 and divide it by 5, that will give you your first question mark.{you should have gotten 60.} To find the second one, you are going to apply the same concept, Take 300 and divide it by 6, giving you your second question mark. {you should have gotten 50}...
P.S.: {hope I helped} :)
Step-by-step answer:
We are looking at the coefficient of the 22nd term of (x+y)^25.
Following the sequence, first term is x^0y^25, second term is x^1y^24, third term is x^2y^23...and so on, 22nd term is x^21y^4.
The twenty-second term of (x+y)^25 is given by the binomial theorem as
( 25!/(21!4!) ) x^21*y^4
=25*24*23*22/4! x^21y^4
= 12650 x^21 y^4
The coefficient required is therefore 12650, for a binomial with unit valued coefficients.
For other binomials, substitute the values for x and y and expand accordingly.
Question would have been more clearly stated if the actual binomial was given, as commented above.
Y=ln(ln(x))
y'=(1/x)/Ln(x)=1/xln(x)
Answer:
-2 Celsius >-5 Celsius is the answer.
Answer:
f(- 2) = - 1
Step-by-step explanation:
To evaluate f(- 2) substitute x = - 2 into f(x) , that is
f(- 2) = 3 - (- 2)² = 3 - 4 = - 1
