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Ulleksa [173]
3 years ago
11

Why is it important for a rainy-day fund to be highly liquid? A. Funds need to earn a high rate of return. B. Funds need to be e

asily accessible. C. Funds need to be stored in a safe place. D. Funds need to be invested to achieve long-term savings goals.
Mathematics
2 answers:
Alenkinab [10]3 years ago
7 0

Answer:

B. Funds need to be easily accessible.

Step-by-step explanation:

It is important for a rainy-day fund to be highly liquid because - Funds need to be easily accessible.

These funds should be easily accessible, without any penalty. Like - a high yield bank account, money market accounts etc.

Gnoma [55]3 years ago
4 0

Answer: B. Funds need to be easily accessible

This is so you can access it easily without paying a penalty

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What is the equation of the line that is parallel to the line 5x + 2y = 12 and passes through the point (-2, 4)?
ludmilkaskok [199]
The answer is Y=-5/2x-1
7 0
3 years ago
Solve x please 2x/3=4
Semenov [28]
Multiply both siase of equation by 3
2x*3/3=4*3
2x=12
devide by 2
2x:2=12:2
x=6
Answer: x=6
7 0
3 years ago
Read 2 more answers
Solve the following inequality: 3-5x-x^2>=0
Dennis_Churaev [7]

Answer:

-5/2+-1/2√37≤x≤-5/2+1/2√37

Step-by-step explanation:

Step 1: Find the critical points

-x^2-5x+3=0

For this equation: a=-1, b=-5, c=3

−1x^2+−5x+3=0

x=−b±√b2−4ac/2a

x=−(−5)±√(−5)2−4(−1)(3)/2(-1)

x=5±√37 /−2

x=-5/2+1/2√37

Step 2: Check intervals in between critical points

x≤-5/2+1/2 √37 (Doesn't work in original inequality)

-5/2+-1/2√37≤x≤-5/2+1/2√37 (Works in original inequality)

x≥-5/2+1/2 √37 (Doesn't work in original inequality)

5 0
3 years ago
Punctele O, A, B, C sunt coliniare în această ordine, iar segmentele OA, AB și BC au lungimile exprimate în cm, prin numere natu
julia-pushkina [17]

Răspuns:

a) OC = 18cm

b) MN = 6cm

Explicație pas cu pas:

Găsiți diagrama la întrebarea atașată.

a) Din diagramă se poate observa că OC = OA + AB + AC

OC = 2n + 2n + 2 + 2n + 4

OC = 6n + 6

Următorul este să obțineți valoarea lui n:

OM = OA + AM

Să obținem segmentul AM;

Deoarece M este segmentul mijlociu al AC, atunci;

AM = AC / 2

AM = AB + BC / 2

AM = 2n + 2 + 2n + 4/2

AM = 4n + 6/2

AM = 2n + 3

Din moment ce OM = OA + AM

OM = 2n + 2n + 3

OM = 4n + 3

Dat fiind OM = 11

11 = 4n + 3

4n = 11-3

4n = 8

n = 2

Următorul pas este să calculați OC;

OC = 6n + 6

OC = 6 (2) + 6

OC = 18

Prin urmare, lungimea segmentului OC este de 18 cm

b) Această întrebare ne cere să găsim segmentul de linie MN.

Din diagramă, MN = AM - AN

Deoarece AM = 2n + 3 din întrebarea 1;

AM = 2 (2) +3

AM = 4 + 3

AM = 7

Acum, să obținem AN:

Din diagramă, AN = ON-OA și ON = OB / 2

AN = OB / 2 - OA

AN = (2n + 2n + 2) / 2 - 2n

AN = 4n + 2/2 - 2n

AN = 2n + 1 - 2n

AN = 2n-2n + 1

AN = 1

De la MN = AM - AN

MN = 7 - 1

MN = 6cm

Prin urmare, distanța dintre N, mijlocul segmentului OB și punctul M este de 6cm

6 0
3 years ago
Find the value of x.<br> 7<br> D<br> 3<br> B В<br> х<br> С<br> X =
bekas [8.4K]

Answer:

x = \sqrt{30}

Step-by-step explanation:

Using the Altitude- on- Hypotenuse theorem

(leg of Δ ABC )² = (part of hypotenuse below it ) × ( whole hypotenuse )

x² = 3 × (3 + 7) = 3 × 10 = 30 ( take the square root of both sides )

x = \sqrt{30}

7 0
3 years ago
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