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3 years ago

8

A man bought a scooter for $100 and sold it for $120. He later bought it back for $140 and sold it again for $160. How much did

he make or lose as a scooter salesman? (NO LINKS WILL REPORT WITH OUT HESITATION)

1 answer:

ziro4ka [17]3 years ago

5 0

Answer:

Step-by-step explanation:

- 100

+ 120 = 20

-140 = -20

+160 = 20

so every time he sold it, he gained 20 and lost 20 every time he bought it back

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Answer:

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Step-by-step explanation:

Let assume that the number of computer produced by factory C is k = 1

So From the question we are told that

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The number produced by factory B is 7k = 7

The probability of defective computers from A is $P(A) = 0.04$

The probability of defective computers from B is $P(B) = 0.02$

The probability of defective computers from C is $P(C) = 0.03$

Now the probability of factory A producing a defective computer out of the 4 computers produced is

$P(a) = 4 * P(A)$

substituting values

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The probability of factory B producing a defective computer out of the 7 computers produced is

$P(b) = 7 * P(B)$

substituting values

$P(b) = 7 * 0.02$

$P(b) = 0.14$

The probability of factory C producing a defective computer out of the 1 computer produced is

$P(c) = 1 * P(C)$

substituting values

$P(c) = 1 * 0.03$

$P(b) = 0.03$

So the probability that the a computer produced from the three factory will be defective is

$P(t) = P(a) + P(b) + P(c)$

substituting values

$P(t) = 0.16 + 0.14 + 0.03$

$P(t) = 0.33$

Now the probability that the defective computer is produced from factory A is

$P(A') = \frac{P(a)}{P(t)}$

$P(A') = \frac{ 0.16}{0.33}$

$P(A') = 0.485$

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