Answer:
t = 3 seconds
Step-by-step explanation:
Here h(t) = -16t^2 + 144.
When the quarter hits the ground, its height will be 0 feet. Letting h(t) = 0 results in -16t^2 + 144 = 0, or 16t^2 = 144, or
144
t^2 = ------------ = 36/4 = 9 seconds^2
16
Therefore, the time, t, required for the quarter to hit the ground is t = √9, or t = 3 seconds
-b/2a is the axis of symmetry formula.
To solve those 4 questions, find the values of a and b (coefficients of ax^2 and bx term) and substitute them into the formula.
Hope this helps!
Redo the question I can’t see the picture
Answer:
11
Step-by-step explanation:
<h2>
<em>OladipoSeun</em><em>♡˖꒰ᵕ༚ᵕ⑅꒱</em></h2>
Answer:
84
Step-by-step explanation:
