Answer:
k can either be
12
or
−
12
.
Step-by-step explanation:
Consider the equation
0=x2+4x+4
. We can solve this by factoring as a perfect square trinomial, so
0=(x+2)2→x=−2 and−2
. Hence, there will be two identical solutions.
The discriminant of the quadratic equation (b2−4ac) can be used to determine the number and the type of solutions. Since a quadratic equations roots are in fact its x intercepts, and a perfect square trinomial will have
2 equal, or 1
distinct solution, the vertex lies on the x axis. We can set the discriminant to 0 and solve:
k2−(4×1×36)=0
k2−144=0
(k+12)(k−12)=0
k=±12
Answer:
- A. segment A double prime B double prime = segment AB over 2
Step-by-step explanation:
<u>Triangle ABC with coordinates of:</u>
- A = (-3, 3), B = (1, -3), C = (-3, -3)
<u>Translation (x + 2, y + 0), coordinates will be:</u>
- A' = (-1, 3), B = ( 3, -3), C = (-1, -3)
<u>Dilation by a scale factor of 1/2 from the origin, coordinates will be:</u>
- A'' = (-0.5, 1.5), B'' = (1.5, -1.5), C= (-0.5, -1.5)
<u>Let's find the length of AB and A''B'' using distance formula</u>
- d = √(x2-x1)² + (y2 - y1)²
- AB = √(1-(-3))² + (-3 -3)² = √4²+6² = √16+36 = √52 = 2√13
- A''B'' = √(1.5 - (-0.5)) + (-1.5 - 1.5)² = √2²+3² = √13
<u>We see that </u>
<u>Now the answer options:</u>
A. segment A double prime B double prime = segment AB over 2
B. segment AB = segment A double prime B double prime over 2
- Incorrect. Should be AB = A''B''*2
C. segment AB over segment A double prime B double prime = one half
- Incorrect. Should be AB/A''B'' = 2
D. segment A double prime B double prime over segment AB = 2
- Incorrect. Should be A''B''/AB = 1/2
2/5 in 1/12 of an hour
x in 1 hour
So multiply 12 to both fractions
2/5 x 12 in 1/12 x 12 of an hour
We get now:
24/5 in 1 hour
or:
4 4/5 in 1 hour
Answer:
C
Step-by-step explanation:
Given
V = πr²h
Isolate h by dividing both sides by πr²
= h → C
