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stellarik [79]
3 years ago
7

Find the common factor of all the terms of the polynomial below 49y^3-7y^2+14y

Mathematics
2 answers:
Nataliya [291]3 years ago
6 0
<span>49y^3-7y^2+14y
= 7y (7y^2 - y + 2)

Common factor is 7y
</span>
Alecsey [184]3 years ago
5 0
<span>49y^3-7y^2+14y

= 7y(7y^2 - y + 2)</span>
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Step-by-step explanation:

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Solve for x in the equation
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Which of the following is not necessarily true for independent events A and B? P (A intersection B )equals P (A )P (B )P (A vert
Sauron [17]

Answer:

P(A U B)=P(A)+P(B)

Step-by-step explanation:

Reading the options that we have for the answer, one of them (the first one) is the definition of being independent. A and B are independent if and only if P(A ∩ B)=P(A)*P(B).

So the first one IS necessary true for independent events and with this equation, option two and three are necessary true for independent events:

For definition of P(A | B)

P(A | B)= P(A ∩ B) / P(B)

And we replace P(A ∩ B) using the first option that we know it´s true:

P(A | B)= P(A)*P(B) / P(B)= P(A)

So P(A | B)=P(A) it´s true for A and B independent.

The same process goes to show P(B | A)=P(B)

Because of this, the only one of the options that could not be true for independent events is P(A ∪ B)=P(A) + P(B), and this happens because P(A ∩ B)=P(A)*P(B) applies but it could be different from 0 considering P(A ∪ B)=P(A) + P(B) - P(A ∩ B). We conclude this property (P(A ∪ B)=P(A) + P(B)) is not necessary true for A and B independent.

6 0
3 years ago
A rectangle has a perimeter of 34 inches. the length is 7 inches longer than the width. the area of this rectangle is __________
SCORPION-xisa [38]
Let x inch be the width
x×2+(x+7)×2=34
2x+2x+14=34
4x=20
x=5
the length=5+7 i.e.12 inches
the width=5 inches
Area=5×12=60 inches
6 0
3 years ago
0.38 as a mixed number​
Katena32 [7]
0.38 is a mixed number could be variables of 0.00
5 0
1 year ago
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