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3 years ago

MATH PLS HELPPP FREE BRAINLIEST!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Sonja [21]3 years ago

7 0

Answer:

All real numbers is the Answer

Step-by-step explanation:

o-na [289]3 years ago

5 0

<u> All real numbers</u> is the answer

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Can someone help me with this equation?

navik [9.2K]

Answer:

so far i think 9 but that's all I know for how

Step-by-step explanation:

image them turning into triangles

5 0

3 years ago

Find the value of m .

kondor19780726 [428]

Step-by-step explanation:

if the 2 matrices are inverse, then their product must be the identity matrix

1 0

0 1

so,

m×3 + 2×-7 = 1

7×3 + 3×-7 = 0

m×-2 + 2×m = 0

7×-2 + 3×m = 1

that means we have to solve only

3m - 14 = 1

3m = 15

m = 5

7 0

3 years ago

Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf

kobusy [5.1K]

Answer:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We have the following data given:

$\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by $\alpha=1-0.93=0.07$ and $\alpha/2 =0.035$ . And the critical value would be given by:

$z_{\alpha/2}=-1.811, z_{1-\alpha/2}=1.811$

The confidence interval is given by:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

4 0

3 years ago

If cos70 = 0.342, give another angle whose cosine is 0.343

Brut [27]

If cos(70) = 0.342
the cosine of the alternative angle of 70° will also give the same value
angle measure = 360 - 70 = 240°
cos (240) will also be 0.342

5 0

3 years ago

What is two times a number n is three times the sum of n and nine

Nonamiya [84]

2n=3(n+9)
2n=3n+27

n = -27

5 0

3 years ago