All categories

3 years ago

Which answers are equal to the expression in the box? Check all that apply. 16 • 25

Mathematics

2 answers:

vova2212 [387]3 years ago

8 0

Answer:

i dont understand what you're trying to say but 16 * 25 = 400

Alisiya [41]3 years ago

3 0

Don’t understand what your trying to say, but the answer is 400

You might be interested in

Does anyone know whoever answers i’ll mark brainlist

-Dominant- [34]

Answer:

(1,2)

Step-by-step explanation:

The solution to the system is where the two lines cross.

They cross at x=1 and y=2

(1,2)

8 0

3 years ago

Please help solve this question with steps

Orlov [11]

39x^3 = 13*3*x*x*x

-6x^2 = 2*3*x*x*-1

-3x = 3*x*-1

so in all these factorizations, 3*x is common. so 3x is the common factor.

by seperating the common factor,

3x(13x^2 - 2x-1)

will be the factorization.

xy + 5x - 5y - 25

=x (y+5) -5 (y+5)
=(x-5) (y+5)

hope I helped ya!!!

8 0

3 years ago

Find the missing Factor of ×9=90

n200080 [17]

Answer:

x=10

Step-by-step explanation:

9×10=90 That is how I got the answer.

5 0

3 years ago

What is a decimal that is equivalent to 63/75

eduard

Answer:

0.84

Step-by-step explanation:

Divide 63 by 75 and you get 0.84 (84%).

7 0

3 years ago

Read 2 more answers

Show that d^2y/dx^2=-2x/y^5, if x^3 + y^3=1

aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

${3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}$

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

$3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}$

3 0

3 years ago