First, divide 1 by 3 and 1 by 2.
1 divided by 3 = <span>0.33333333333
1 divided by 2 = 0.5
Add them up. </span>0.33333333333 + 0.5 = <span>0.83333333333.
Divide </span>0.83333333333 by 2, since there are 2 numbers we added up. 0.83333333333 / 2 = 0.41666666666, and <span>0.41666666666 as a fraction is 5/12.</span>
Answer: Domain: (1,+inf) range (1800,inf)
Step-by-step explanation:
assuming that he cant sell negative cars or 0 cars this is the domain and range
Answer:
Step-by-step explanation:
Answer: This is impossible because the absolute value function can never result in a negative number.
Answer:
Step-by-step explanation:
When learning about commutative and associative properties, we learn that ...
a + b = b + a . . . . . addition is commutative
ab = ba . . . . . . . . . multiplication is commutative
But we also know that ...
a - b ≠ b - a . . . . . . subtraction is not commutative
a/b ≠ b/a . . . . . . . . division is not commutative
__
We also learn that ...
a + (b+c) = (a+b) +c . . . . addition is associative
a(bc) = (ab)c . . . . . multiplication is associative
And of course, ...
a - (b -c) ≠ (a -b) -c . . . . subtraction is not associative
a/(b/c) ≠ (a/b)/c . . . . . . . division is not associative
_____
However, you can use associative and commutative properties in problems involving subtraction and division if you write the expression properly:
a - (b - c) = a +(-(b -c)) = a +((-b) +c) = (a +(-b)) +c . . . . keeping the sign with the value makes it an addition problem, so the associative property can apply
(a/b)/c = (a(1/b))(1/c) = a(1/b·1/c) = writing the division as multiplication by a reciprocal makes it so the associative property can apply
