Question

"A baseball player comes to bat 4 times in a game. The chance of a strike-out for this player is 30%. What is the probability that the player does not strike out for the entire game?

Answer 1

Answer:  0.2401

Step-by-step explanation:

Given : A baseball player comes to bat 4 times in a game

The probability that a strike-out for this player= 0.30

The binomial probability distribution :-

$P(x)=^nC_xp^x(1-p)^{n-x}$, where P(X) is the probability of getting success in x trials, n is the total number of trials and p is the probability of success in each trial ( in  decimal ).

Now,  the probability that the player does not strike out for the entire game :-

$P(x)=^4C_0(0.3)^0(0.7)^{4}\\\\=(0.7)^{4}\\\\=0.2401$

Hence, the required probability = 0.2401