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4 years ago

What whole number comes right before 105?

Mathematics

2 answers:

Marta_Voda [28]4 years ago

7 0

Answer:

104

Step-by-step explanatio

lorasvet [3.4K]4 years ago

3 0

Answer:

104

Step-by-step explanation:

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Use the correct notation to express the follow objects.

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3 years ago

Ely’s team scored 62, 76, 53, and 70 points in their first four basketball games. How many points does the team need to score in

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89 is the amount of points the team needs to score in the fifth game to average 70 points.

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3 years ago

Which shows the phrase "the product of a number and 3" as a variable expression?

JulijaS [17]

The algebraic expression for the word phrase "the product of a number and 3" as a variable expression is 3z

<h3>How to write an algebraic expression for the word phrase "the product of a number and 3" as a variable expression?</h3>

The word phrase is given as:

"the product of a number and 3"

Represent the number with z

So, the word phrase can be rewritten as:

"the product of a number z and 3"

The product of a number z and 3 is represented as:

z * 3

When evaluated,, the expression becomes

z * 3 = 3z

Hence, the algebraic expression for the word phrase "the product of a number and 3" as a variable expression is 3z

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2 years ago

In a recent survey in a Statistics class, it was determined that only 70% of the students attend class on Fridays. From past dat

pishuonlain [190]

Answer:

a) 67.6% of students is expected to pass the course

b) 0.9112 = 91.12% probability that he/she attended classes on Fridays

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

a. What percentage of students is expected to pass the course?

88% of 70%(attended class)

20% of 100 - 70 = 30%(did not attend class). So

$p = 0.88*0.7 + 0.2*0.3 = 0.676$

0.676*100% = 67.6%

67.6% of students is expected to pass the course.

b. Given that a person passes the course, what is the probability that he/she attended classes on Fridays?

Here, we use conditional probability:

Event A: Passed the course

Event B: Attended classes on Fridays.

67.6% of students is expected to pass the course.

This means that $P(A) = 0.676$

Probability that passed and attended classes on Friday.

88% of 70%

This means that:

$P(A \cap B) = 0.88*0.7 = 0.616$

Then

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.616}{0.676} = 0.9112$

0.9112 = 91.12% probability that he/she attended classes on Fridays

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3 years ago

A restaurant owner has found that 80% of her customers return to the restaurant within two weeks. She wants to create a tool tha

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Answer:

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3 years ago

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