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VashaNatasha [74]
3 years ago
15

Complete the tables of values.

Mathematics
2 answers:
zlopas [31]3 years ago
6 0

<u>Answer with Step-by-step explanation:</u>

We are given two tables and we are to complete the missing values.

For table one, we are to substitute the given values of x in the term 4^{-x}:

when x = 0, 4^{-0} = 1

when x = 2, 4^{-2} = \frac{1}{16}

when x = 4, 4^{-4} = \frac{1}{256}

For table two, we are to substitute the given values of x in the term (\frac{2}{3} )^x:

when x = 0, (\frac{2}{3} )^0 = 1

when x = 2, (\frac{2}{3} )^2 = \frac{4}{9}

when x = 4, (\frac{2}{3} )^4 = \frac{16}{81}

Lana71 [14]3 years ago
3 0

Answer:

for f(x) =4^{-x} the value a=1,\ b=\frac{1}{16},\ c=\frac{1}{256}

for  f(x) =(\frac{2}{3})^{x} the value a=1,\ b=\frac{4}{9},\ c=\frac{16}{81}

Step-by-step explanation:

Consider

1 ) f(x) =4^{-x}

We have to find the values at certain given points.

at x = 0

f(0) =4^{-0}=4^0=1

at x = 2

f(2) =4^{-2}=\frac{1}{4^2}=\frac{1}{16}

at x= 4

f(4) =4^{-4}=\frac{1}{4^4}=\frac{1}{256}

Thus, a=1,\ b=\frac{1}{16},\ c=\frac{1}{256}

Consider

2)  f(x) =(\frac{2}{3})^{x}

We have to find the values at certain given points.

at x = 0

f(x) =(\frac{2}{3})^{0}=1

at x = 2

f(x) =(\frac{2}{3})^{2}=(\frac{4}{9})

at x = 4

f(x) =(\frac{2}{3})^{4}=\frac{16}{81}

Thus, a=1,\ b=\frac{4}{9},\ c=\frac{16}{81}

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