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Sophie [7]
3 years ago
10

Which graph represents a linear function

Mathematics
1 answer:
Svetllana [295]3 years ago
7 0

Answer:

the second one iy s very incorrect

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Help me out please an thank you
Aliun [14]

Answer:

The angles that are supplementary to angle 7 includes angle 5 and angle 8.

4 0
2 years ago
A rectangular garden has a perimeter of 36 yards and a width of 8 yards.
xeze [42]

Answer:

80 square yards

Step-by-step explanation:

We know we have a width of 8 yards and a perimeter of 36.

how I figured it out was:

36=(8*2) * (x*2)

8*2=16

36-16=10

So now we know the length and width.

area of a rectangle is lw (length * width)

10*8=80.

8 0
3 years ago
Given two points (2, 7) and (1, -2) on a line, calculate the slope of the line.
Kipish [7]

Answer:

Step-by-step explanation:

Slope of line passing through (2, 7) and (1, -2) = (-2-7)/(1-2) = 9

7 0
2 years ago
Please solve this problem.
just olya [345]

x=number of oranges.

y=number of bananas.

$5

we can suggest this system of equations:

x+y=12

0.5x+0.25y=5

We can solve this system of equations by substitution method.

x=12-y

0.5(12-y)+0.25y=5

6-0.5y+0.25y=5

-0.25y=5-6

-0.25y=-1

y=-1 /- 0.25=4

x=12-y

x=12-4=8

Answer:

<em>Tanya bought 8 oranges and 4 bananas.</em>

4 0
2 years ago
Read 2 more answers
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro
Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of \pi, so we use the worst case scenario, which is \pi = 0.5

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}

n = 1067.11

Rounding up

A sample of 1068 is needed.

8 0
2 years ago
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