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Olin [163]
3 years ago
8

A box in the shape of a rectangular prism, with dimensions 12 inches by 18 inches by 12 inches, can hold exactly 12 cubes measur

ing 6 inches on each side.
If the length and width of the base are doubled, how many cubes could the new box hold?

18
24
48
96
Mathematics
1 answer:
Nitella [24]3 years ago
6 0

Answer:  48 cubes in the new box

Step-by-step explanation:

Doubling the length and the width is 2×2, so 4 times the original capacity.

4×12 = 48

It is not necessary to compute the volume. The dimensions could be anything. It's the number of cubes that count.

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If -3(y-1)=9 find the value of 1/2y
Sveta_85 [38]

Answer:

-1

Step-by-step explanation:

y-1=-3

y=-2

.:1/2y=1/2(-2)=-1

4 0
3 years ago
X= 0 , 1 , or 7<br> Y= -10, 5, or 10<br> Please helppppp will mark Brainliest
vlabodo [156]

Step-by-step explanation:

6 0
3 years ago
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Juliette [100K]

Answer:

A. moving forward for 10m at a steady pace of 2m/s

B. moving backwards 8m at a steady pace of 2.67m/s

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5 0
3 years ago
What is √-11 in the form a+bi?
Mice21 [21]

Given:

The number is \sqrt{-11}.

To find:

The a+bi form of given number.

Solution:

We have,

\sqrt{-11}

It can be written as

\sqrt{-11}=\sqrt{-1\times 11}

\sqrt{-11}=\sqrt{-1}\times \sqrt{11}      [\because \sqrt{ab}=\sqrt{a}\sqrt{b}]

\sqrt{-11}=i\times \sqrt{11}      [\because \sqrt{-1}=i]

\sqrt{-11}=\sqrt{11}i

Here, real part is missing. So, it can be taken as 0.

\sqrt{-11}=0+\sqrt{11}i

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3 years ago
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2 years ago
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