Answer:
Number of times new computer faster than old computer = 13.90 times (Approx)
Explanation:
Given:
Clock speed of old computer = 266 MHz
Clock speed of new computer = 3.7 GHz
266MHz = 0.266GHz
Find:
Number of times new computer faster than old computer
Computation:
Number of times new computer faster than old computer = Clock speed of new computer / Clock speed of old computer
Number of times new computer faster than old computer = 3.7 / 266
Number of times new computer faster than old computer = 3.7 / 0.266
Number of times new computer faster than old computer = 13.90 times (Approx)
Answer:
You have very little or limited amounts of an item(s).
Explanation:
Contactles..........................................................
If the solution
process is endothermic, then an increase in temperature usually results in an
increase in solubility. Their heat of reaction is usually positive. The rest of
the choices do not answer the question above.
