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gregori [183]
2 years ago
15

What are the 3 rules of music ps: there is no music subject so i had to put something else

Computers and Technology
2 answers:
Kitty [74]2 years ago
7 0

Answer:

Rules that apply to all situations and accasions in the music room

Explanation:

I hope this helps

cupoosta [38]2 years ago
5 0

Answer:

playing at any one time in your song 2,working beyond 3or 4 elements at once can crowd your track 3,making it harder for your audience to connect and recall ur composition

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Which are methods used to improve reading fluency? Check all that apply. Practicing with a weak reader listening to a fluent rea
valina [46]

Answer:

listening to a fluent reader, developing vocabulary monitoring progress, reading a text once rereading a text

Explanation:

6 0
3 years ago
Read 2 more answers
Which of these statements are true about domain controllers (dcs)? check all that apply.
KATRIN_1 [288]

The statement that applies are:

  • The default Organizational Unit (OU) called Domain Controllers contains all Domain Controllers in the domain
  • Delegation can be used in Active Directory

A domain controller is simply known as a server that gives its response to authentication requests by individuals and also verifies users on networks in computer. They often occurs in an hierarchical way of putting users and computers that work together on the same network.

It act a the box that is in charge of holding the keys to the kingdom that is the Active Directory. It uses delegation that is given or putting together users and network when working in the active directory.

Conclusively we can say that

domain controller uses delegation in Active Directory

Learn more from

brainly.com/question/17109221

5 0
2 years ago
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Homework Assignment 2 1. Consider the skeletal definition for a class called circle given as: public class Circle { private int
jek_recluse [69]

Answer:

See explaination

Explanation:

public class Circle {

private double radius;

private Location location;

private String name;

/* (non-Javadoc)

* atsee java.lang.Object#hashCode()

*/

atOverride

public int hashCode() {

final int prime = 31;

int result = 1;

result = prime * result + ((location == null) ? 0 : location.hashCode());

long temp;

temp = Double.doubleToLongBits(radius);

result = prime * result + (int) (temp ^ (temp >>> 32));

return result;

}

/* (non-Javadoc)

* atsee java.lang.Object#equals(java.lang.Object)

*/

atOverride

public boolean equals(Object obj) {

if (this == obj)

return true;

if (obj == null)

return false;

if (getClass() != obj.getClass())

return false;

Circle other = (Circle) obj;

if (location == null) {

if (other.location != null)

return false;

} else if (!location.equals(other.location))

return false;

if (Double.doubleToLongBits(radius) != Double.doubleToLongBits(other.radius))

return false;

return true;

}

NOTE: Replace all the "at" within the program with the at symbol ie shift 2.

3 0
3 years ago
You are working for the census bureau and you need to write a program in C to do the following: a) count the number of people in
valina [46]

Answer:

See explaination

Explanation:

#include<iostream>

#include<stdio.h>

#include<conio.h>

#include<math.h>

using namespace std;

void main()

{

int RandomData[]={10,5,20,45,20,66,25,31,20,70}; //Random Data

int infant=0,young=0,middle=0,old=0,older=0; //To store count

int n,freq,count=0,high=0; //to store mode and other

double stdDev,mean,sum=0; //to store stdDev mean and sum

for(int i=0;i<(sizeof(RandomData)/sizeof(RandomData[0]));i++) //loop to count

{

if(RandomData[i]>0&&RandomData[i]<=18)

infant++;

else if(RandomData[i]>18&&RandomData[i]<=29)

young++;

else if(RandomData[i]>29&&RandomData[i]<=50)

middle++;

else if(RandomData[i]>50&&RandomData[i]<=69)

old++;

else if(RandomData[i]>69)

older++;

}

double first=0,sec=0; //to store result of stdDev formula first and second part

for(int i=0;i<(sizeof(RandomData)/sizeof(RandomData[0]));i++) //loop to calculate mean mode and stdDev

{

n=RandomData[i];

count=0;

for(int j=0;j<(sizeof(RandomData)/sizeof(RandomData[0]));j++)

{

if(n==RandomData[j])

count++;

}

if(high<count)

{

freq=RandomData[i];

high=count;

}

first+=(pow((RandomData[i]),2)/(sizeof(RandomData)/sizeof(RandomData[0])));

sec+=RandomData[i]/(sizeof(RandomData)/sizeof(RandomData[0]));

sum+=RandomData[i];

}

mean=sum/(sizeof(RandomData)/sizeof(RandomData[0]));

stdDev=sqrt(first-pow((sec),2));

/*------Printing Result-----*/

cout<<"\nCount:\nInfant: "<<infant<<"\nYoung: "<<young<<"\nMiddle: "<<middle;

cout<<"\nOld: "<<old<<"\nOlder: "<<older;

cout<<"\n\nMean: "<<mean<<"\nMode: "<<freq<<"\nStandard Deviation: "<<stdDev;

/*-----------XXXX-------------*/

getch();

}

8 0
2 years ago
Read the following scenario and decide whether it is fair use and why Donnie has a major paper do for school he finds a great we
ss7ja [257]

Answer:

(A) and (B) I'm leaning more towards (B)

Explanation:

5 0
3 years ago
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