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gregori [183]
3 years ago
15

What are the 3 rules of music ps: there is no music subject so i had to put something else

Computers and Technology
2 answers:
Kitty [74]3 years ago
7 0

Answer:

Rules that apply to all situations and accasions in the music room

Explanation:

I hope this helps

cupoosta [38]3 years ago
5 0

Answer:

playing at any one time in your song 2,working beyond 3or 4 elements at once can crowd your track 3,making it harder for your audience to connect and recall ur composition

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Which of the following cannot be used in MS Office.<br> Joystick<br> Scanner<br> Light Pen<br> Mouse
ValentinkaMS [17]

Answer:

A.

Explanation:

A Joystick is a control device that is connected to the computer to play games. A joystick is similar in structure to a control stick used by pilots in airplanes and got its name from the same. A joystick contains a stick, base, extra buttons, auto switch fire, trigger, throttle, POV hat, and a suction cup. A joystick also serves the purpose of assistive technology.

The device which can not be used in MS Office is a joystick. Therefore, option A is correct.

6 0
3 years ago
9 dmz, vpn, vlan where in the network do you place a dmx, why, what attacks are prevented? what does a vpn do, provide an exampl
creativ13 [48]

At the: Firewall, the DMZ is configured in the Organization. Within the firewalls, it is accessible. They have been completed with the intention of adding an additional layer of safety to the organization to protect it.

The DMZ safeguards not only the web server but also the remainder of the network. To allow visitors to the network to access the web server, a security breach must be made.

The DMZ lessens the possible risk caused by this gap. A secure network, protected by the FortiGate, that only permits access if it has been specifically authorized is known as a DMZ network (from the term "demilitarized zone").

In this illustration, a private subnet is used by the DMZ network, which permits access to a web server by internal and external users using distinct addresses while blocking access from the web server to the internal network in the case that the web server is compromised.

To know more about DMZ click on the link:

brainly.com/question/2920815

#SPJ4

7 0
1 year ago
Im bored anyone up for a convo? lets talk.. =D
aleksandrvk [35]

Answer:

ok im fine with dat <3

6 0
3 years ago
Read 2 more answers
Technically a coding question utilizing python how would one calculate a square root
WITCHER [35]

Answer:

import math

math.sqrt( x )

Explanation:

The basic code that can be written to calculate the square root of a number is as follows

import math

math.sqrt( x )

5 0
3 years ago
In this assignment, you will create a flashcard app for teaching addition and multiplication. The student will choose the type o
Anna11 [10]

Answer:

See explaination

Explanation:

import java.util.*;

import java.lang.Math;

public class Main

{

public static double getRandomDoubleBetweenRange (double min, double max)

{

double x = (Math.random () * ((max - min) + 1)) + min;

return x;

}

public static void main (String[]args)

{

int option, number_of_problems, correct_answer;

double max_operand, average =

0, user_answer, sum, first_number, second_number, multiply,

sum_or_multiply;

Scanner user_input = new Scanner (System.in);

do

{

System.out.println

("Choose the type of problem: \n1. Addition \n2. Multiplication \n3. Mixed \n4. Quit");

option = user_input.nextInt ();

switch (option)

{

case 1:

correct_answer = 0;

System.out.println ("How many problems?");

number_of_problems = user_input.nextInt ();

System.out.println ("Largest operand?");

max_operand = user_input.nextDouble ();

for (int i = 0; i < number_of_problems; i++)

{

first_number = getRandomDoubleBetweenRange (0, max_operand);

second_number = getRandomDoubleBetweenRange (0, max_operand);

System.out.println (first_number + " + " + second_number +

" = ?");

user_answer = user_input.nextDouble ();

sum = first_number + second_number;

if (sum == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.out.println ("Incorrect, The Correct answer is " +

sum);

}

}

average = correct_answer * 100 / number_of_problems;

System.out.println ("You answered " + correct_answer +

" out of " + number_of_problems +

" correctly. Your average was " + average);

break;

case 2:

correct_answer = 0;

System.out.println ("How many problems?");

number_of_problems = user_input.nextInt ();

System.out.println ("Largest operand?");

max_operand = user_input.nextDouble ();

for (int i = 0; i < number_of_problems; i++)

{

first_number = getRandomDoubleBetweenRange (0, max_operand);

second_number = getRandomDoubleBetweenRange (0, max_operand);

System.out.println (first_number + " * " + second_number +

" = ?");

user_answer = user_input.nextDouble ();

multiply = first_number * second_number;

if (multiply == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.out.println ("Incorrect, The Correct answer is " +

multiply);

}

}

average = correct_answer * 100 / number_of_problems;

System.out.println ("You answered " + correct_answer +

" out of " + number_of_problems +

" correctly. Your average was " + average);

break;

case 3:

correct_answer = 0;

System.out.println ("How many problems?");

number_of_problems = user_input.nextInt ();

System.out.println ("Largest operand?");

max_operand = user_input.nextDouble ();

for (int i = 1; i <= number_of_problems; i++)

{

first_number = getRandomDoubleBetweenRange (0, max_operand);

second_number = getRandomDoubleBetweenRange (0, max_operand);

if (i % 2 == 1)

{

System.out.println (first_number + " + " + second_number +

" = ?");

user_answer = user_input.nextDouble ();

sum_or_multiply = first_number + second_number;

if (sum_or_multiply == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.

out.println ("Incorrect, The Correct answer is " +

sum_or_multiply);

}

}

else

{

System.out.println (first_number + " * " + second_number +

" = ?");

user_answer = user_input.nextDouble ();

sum_or_multiply = first_number * second_number;

if (sum_or_multiply == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.

out.println ("Incorrect, The Correct answer is " +

sum_or_multiply);

}

}

}

average = correct_answer * 100 / number_of_problems;

System.out.println ("You answered " + correct_answer +

" out of " + number_of_problems +

" correctly. Your average was " + average);

break;

case 4:

System.out.println ("Thanks for playing.");

break;

default:

System.out.println ("Please choose a valid option");

break;

}

}

while (option != 4);

}

}

3 0
3 years ago
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